MySQL Workbench - MySQL 语法错误

Question

MySQL 工作台是一个很棒的工具，但您必须保持头脑清醒，因为它不进行任何错误检查。

因此，它生成了此 SQL 语法来创建表，但它不起作用。 我不明白为什么

它给了我这个错误:

#1064 - You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version
for the right syntax to use near
') NULL DEFAULT NULL , `maaltijd` TINYINT(1) NOT NULL ,
`cheques` TINYINT(1'
at line 14

这是查询:

    CREATE  TABLE IF NOT EXISTS `nascholing`.`aanvraag` (
      `aanvraagId` INT(11) NOT NULL AUTO_INCREMENT ,
      `userId` BIGINT(20) NOT NULL ,
      `creationDate` DATETIME NULL DEFAULT NULL ,
      `vakGroep` INT(11) NULL DEFAULT NULL ,
      `personeelType` INT(11) NOT NULL ,
      `leeftijd` INT(11) NULL DEFAULT NULL ,
      `thema` VARCHAR(255) NOT NULL ,
      `intern` TINYINT(1) NULL DEFAULT -1 ,
      `duur` INT(11) NOT NULL ,
      `tijdens` INT(11) NULL DEFAULT NULL ,
      `type` INT(11) NULL DEFAULT NULL ,
      `voor` INT(11) NOT NULL ,
      `kost` DOUBLE(11) NULL DEFAULT NULL ,
      `maaltijd` TINYINT(1) NOT NULL ,
      `cheques` TINYINT(1) NOT NULL ,
      `betalingsmethode` INT(11) NOT NULL ,
      `aanschafBoek` TINYINT(1) NOT NULL ,
      `kostBoek` DOUBLE(11) NULL DEFAULT NULL ,
      PRIMARY KEY (`aanvraagId`) ,
      UNIQUE INDEX `aanvraagId_UNIQUE` (`aanvraagId` ASC) ,
      INDEX `fk_aanvraag_user1` (`userId` ASC) ,
      INDEX `fk_aanvraag_duur1` (`duur` ASC) ,
      INDEX `fk_aanvraag_tijdens1` (`tijdens` ASC) ,
      INDEX `fk_aanvraag_type1` (`type` ASC) ,
      INDEX `fk_aanvraag_vakGroep1` (`vakGroep` ASC) ,
      INDEX `fk_aanvraag_voorEmail1` (`voor` ASC) ,
      INDEX `fk_aanvraag_betalingsMethode1` (`betalingsmethode` ASC) ,
      CONSTRAINT `fk_aanvraag_user1`
        FOREIGN KEY (`userId` )
        REFERENCES `nascholing`.`user` (`userId` )
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `fk_aanvraag_duur1`
        FOREIGN KEY (`duur` )
        REFERENCES `nascholing`.`duur` (`duurId` )
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `fk_aanvraag_tijdens1`
        FOREIGN KEY (`tijdens` )
        REFERENCES `nascholing`.`tijdens` (`tijdensId` )
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `fk_aanvraag_type1`
        FOREIGN KEY (`type` )
        REFERENCES `nascholing`.`type` (`typeId` )
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `fk_aanvraag_vakGroep1`
        FOREIGN KEY (`vakGroep` )
        REFERENCES `nascholing`.`vakGroep` (`vakGroepId` )
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `fk_aanvraag_voorEmail1`
        FOREIGN KEY (`voor` )
        REFERENCES `nascholing`.`voorEmail` (`voorEmailId` )
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `fk_aanvraag_betalingsMethode1`
        FOREIGN KEY (`betalingsmethode` )
        REFERENCES `nascholing`.`betalingsMethode` (`betalingsMethodeId` )
        ON DELETE NO ACTION
        ON UPDATE NO ACTION)
    ENGINE = InnoDB
    DEFAULT CHARACTER SET = utf8
    COLLATE = utf8_general_ci;

Answer 1

类型 double 需要指定小数点

示例，

`kost` DOUBLE(11, 2) NULL DEFAULT NULL, ...

所有 double 类型依此类推