由于某种原因，我的表单没有检查数据库以查看电子邮件是否已存在。您能找出我的代码有什么问题吗？
// If the form submit button is set and the email and zip fields are not empty, proceed and process
if (isset($_POST['submit']) && !empty($_POST['email']) && !empty($_POST['zip'])) {
// Create variables for form input fields
$email = $_POST['email'];
$zip = $_POST['zip'];
// Create an array to capture errors
$errors = array();
// Create variable to capture success message
$success = "Thanks for signing up!";
// Email Validation
// Check to see if user entered a valid email
if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
$errors[] = "Invalid email address.";
}
// Check email length
if (strlen($email) < 6) {
$errors[] = "Sorry your email is too short.";
}
// Check email length
if (strlen($email) > 50) {
$errors[] = "Sorry your email is too long.";
}
// Zip Code Validation
// Check to see if zip code is a number
if (!is_numeric($zip)) {
$errors[] = "Zip code must be a number.";
}
// Check to see if zip code equals 5 characters
if (strlen($zip) != 5) {
$errors[] = "Sorry not a valid zip code.";
}
// Include database config file and establish db connection
require("includes/config.php");
$connection = mysql_connect(DB_HOST,DB_USERNAME,DB_PASSWORD) or die("Database Connection Error");
$database = mysql_select_db(DB_NAME) or die("No Database Found");
// Check to see if email already exists in database
$email_check_query = "SELECT email FROM shotgun";
$run_email_check_query = mysql_query($email_check_query);
// If MySQL query returns any results, user has already signed up
if (mysql_fetch_assoc($run_email_check_query) == $email) {
$errors[] = "Looks like you already signed up...";
}
// If there are no errors above run this block of code
if (count($errors) == 0) {
// Include database config file and establish db connection
require("includes/config.php");
$connection = mysql_connect(DB_HOST,DB_USERNAME,DB_PASSWORD) or die("Database Connection Error");
$database = mysql_select_db(DB_NAME) or die("No Database Found");
// Insert email and password into database
$insert_email_query = "INSERT INTO shotgun (email,zip) VALUES ('$email','$zip')";
$run_insert_email_query = mysql_query($insert_email_query);
}
}
?>
地点
</head>
<body>
<header>
<div class="logo">
<h1>Site</h1>
</div>
</header>
<div class="content">
<div class="comingsoon"></div>
<h1>Sign Up Now</h1>
<p class="description">Description</p>
<form action="index.php" method="post">
<input type="email" class="email" name="email" placeholder="Email Address">
<input type="text" class="zip" name="zip" max="5" placeholder="Zip Code">
<input type="submit" class="submit" name="submit" value="Submit">
<span class="errors">
<?php
if (count($errors) != 0) {
foreach($errors as $error) {
echo $error . "<br />";
}
} else {
echo $success;
}
?>
</span>
</form>
</div>
<footer><a href="test.com" title="test"></a></footer>
</body>
最佳答案
$email_check_query = "SELECT email FROM datingshotgun";
应该是
$email_check_query = "SELECT email FROM datingshotgun WHERE email='$email'";
现在，您总是查询所有电子邮件并将新电子邮件与数据库中的第一封电子邮件进行比较。
编辑:跟踪代码后，您需要:
$dbemail=mysql_real_escape_string($email, $connection);
$email_check_query = "SELECT email FROM datingshotgun WHERE email='$dbemail'";
关于php - 让我的 PHP 表单成功查询数据库以检查电子邮件是否已存在时出现问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/8928587/