php - Ajax 分页,php 返回整个页面而不是分页的 div

标签 php javascript jquery mysql ajax

我有一个 php 网站,它必须以分页格式在页面上显示项目列表。我使用 php 实现了这一点,但现在我想向它添加 ajax 功能。所以我添加了这个函数,以便在单击时调用分页部分中的页码。 Ajax/Jquery函数:(.paginate是页面链接的类)

$(document).ready(function()
{
$('.paginate').live('click', function(e)
{
    //alert("Here");
    e.preventDefault();
    var btnPage = $(this);
    //alert(btnPage.attr('href'));     /RealEstate/process.php?page=3&ipp=2&venue=Array $('#temp').load($(this).attr("href")+' #temp');
    var getUrl = btnPage.attr('href');
    //var dataLocality = { 'locality[]' : []};
    //alert(getUrl);
    $.ajax(
    {
       url:btnPage.attr('href'),
        success : function(resp)
        {
            // replace current results with new results.
            $('#project_section').html(resp);
        },
        error : function()
        {
            window.location.href = btnPage.attr('href');
        }
    });
 });
});

我的分页函数有点像这样:

function paginate()
{
    if(!isset($this->default_ipp)) $this->default_ipp='2';
    if($_GET['ipp'] == 'All')
    {
        $this->num_pages = 1;

    }
    else
    {
        if(!is_numeric($this->items_per_page) OR $this->items_per_page <= 0) $this->items_per_page = $this->default_ipp;
        $this->num_pages = ceil($this->items_total/$this->items_per_page);
    }
    $this->current_page = (isset($_GET['page'])) ? (int) $_GET['page'] : 1 ; // must be numeric > 0
    $prev_page = $this->current_page-1;
    $next_page = $this->current_page+1;
    if($_GET)
    {
        $args = explode("&",$_SERVER['QUERY_STRING']);
        foreach($args as $arg)
        {
            $keyval = explode("=",$arg);
            if($keyval[0] != "page" And $keyval[0] != "ipp") $this->querystring .= "&" . $arg;
        }
    }

    if($_POST)
    {
        foreach($_POST as $key=>$val)
        {
            if($key != "page" And $key != "ipp") $this->querystring .= "&$key=$val";
        }
    }
    if($this->num_pages > 4)
    {
        $this->return = ($this->current_page > 1 And $this->items_total >= 10) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$prev_page&ipp=$this->items_per_page$this->querystring\">&laquo; Previous</a> ":"<span class=\"inactive\" href=\"#\">&laquo; Previous</span> ";

        $this->start_range = $this->current_page - floor($this->mid_range/2);
        $this->end_range = $this->current_page + floor($this->mid_range/2);

        if($this->start_range <= 0)
        {
            $this->end_range += abs($this->start_range)+1;
            $this->start_range = 1;
        }
        if($this->end_range > $this->num_pages)
        {
            $this->start_range -= $this->end_range-$this->num_pages;
            $this->end_range = $this->num_pages;
        }
        $this->range = range($this->start_range,$this->end_range);

        for($i=1;$i<=$this->num_pages;$i++)
        {
            if($this->range[0] > 2 And $i == $this->range[0]) $this->return .= " ... ";
            // loop through all pages. if first, last, or in range, display
            if($i==1 Or $i==$this->num_pages Or in_array($i,$this->range))
            {
                $this->return .= ($i == $this->current_page And $_GET['page'] != 'All') ? "<a title=\"Go to page $i of $this->num_pages\" class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" title=\"Go to page $i of $this->num_pages\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> ";
            }
            if($this->range[$this->mid_range-1] < $this->num_pages-1 And $i == $this->range[$this->mid_range-1]) $this->return .= " ... ";
        }
        $this->return .= (($this->current_page < $this->num_pages And $this->items_total >= 10) And ($_GET['page'] != 'All') And $this->current_page > 0) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$next_page&ipp=$this->items_per_page$this->querystring\">Next &raquo;</a>\n":"<span class=\"inactive\" href=\"#\">&raquo; Next</span>\n";
        $this->return .= ($_GET['page'] == 'All') ? "<a class=\"current\" style=\"margin-left:10px\" href=\"#\">All</a> \n":"<a class=\"paginate\" style=\"margin-left:10px\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n";
    }
    else
    {
        for($i=1;$i<=$this->num_pages;$i++)
        {
            $this->return .= ($i == $this->current_page) ? "<a class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> ";
        }
        $this->return .= "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n";
    }
    $this->low = ($this->current_page <= 0) ? 0:($this->current_page-1) * $this->items_per_page;
    if($this->current_page <= 0) $this->items_per_page = 0;
    $this->limit = ($_GET['ipp'] == 'All') ? "":" LIMIT $this->low,$this->items_per_page";
}

在我想要显示分页div的页面上,我得到整个页面作为响应,而不是分页div。我已将分页 div 分离到一个单独的页面并将其包含在显示页面上(下面添加了代码),但不起作用。

<div id="project_section">
    <?php include_once("cityPropertySearchResults.php");?>        
</div>

有人可以解释一下吗?
更新: 我发现类似的东西here

这适用于链接,但现在,所有 js 文件都会递归地一次又一次加载。

感谢您的宝贵时间。

最佳答案

在第一页加载后,首先将限制起始值指定为 0,增加限制起始值作为每页的限制,并通过 ajax 传递该值,并在查询中使用该限制起始值(例如 SELECT * FROM tbl LIMIT 0,10 ;)

关于php - Ajax 分页,php 返回整个页面而不是分页的 div,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11240565/

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