ios - 共享图片点击即可打开 URL

Question

我正在使用 - FBSDKShareKit (4.40.0): 我想在 Facebook 上分享图片。它应该是可点击的，并且应该像 Endomondo 应用程序一样打开网站。

我已经尝试过这段代码，但 url 覆盖了照片并且它们没有显示:

    let sharePhoto = FBSDKSharePhoto()
    sharePhoto.image = someImage

    let content = FBSDKSharePhotoContent()
    content.photos = [sharePhoto];
    content.contentURL = URL(string: "https://facebook.com")!
    FBSDKShareDialog.show(from: self, with: content, delegate: nil)

他们是怎么做到的？

Answer 1

使用它在 Facebook 上分享

导入社交

func shareToFb(_ yourImage:UIImage!)

    {
     let facebookURL = URL(string: "fb://")
      if (UIApplication.shared.canOpenURL(facebookURL!)) {
      let vc = SLComposeViewController(forServiceType:SLServiceTypeFacebook)
             vc?.add(yourImage)
                    vc?.setInitialText("Initial text here.")
                    self.present(vc!, animated: true, completion: nil)
                }
                else {
                    let urlStr = "https://itunes.apple.com/us/app/workplace-by-facebook/id944921229?mt=8"
                    if #available(iOS 10.0, *) {
                        UIApplication.shared.open(URL(string: urlStr)!, options: [:], completionHandler: nil)

                    } else {
                        UIApplication.shared.openURL(URL(string: urlStr)!)
                    }
                }


            }