ios - signInWithPhoneNumber() 在 react native 中不起作用

Question

嗨，我在

中收到此错误

firebase.auth().signInWithPhoneNumber(phoneNumber)

Error Domain=FIRAuthErrorDomain Code=17057 "User interaction is still ongoing, another view cannot be presented." UserInfo={NSLocalizedDescription=User interaction is still ongoing, another view cannot be presented., FIRAuthErrorUserInfoNameKey=ERROR_WEB_CONTEXT_ALREADY_PRESENTED}

在 RNFirebaseAuth.m 中。

这里有错误

const confirmResult = await firebase.auth().signInWithPhoneNumber(phoneNumber);
      if (confirmResult) {
        this.setState({
          confirmResult,
          message: 'Code has been sent!',
          step: 2,
        }, this.goToEnterOtpScreen());
      }

来自 native 模块的非法回调调用。此回调类型仅允许从 native 代码进行单次调用。

"react-native-firebase": "^5.5.4",



 pod 'Firebase/Core', '~> 6.3.0'

  pod 'Firebase/Auth', '~> 6.3.0'
  pod 'Firebase/Database', '~> 6.3.0'
  pod 'Firebase/Functions', '~> 6.3.0'
  pod 'Firebase/DynamicLinks', '~> 6.3.0'
  pod 'Firebase/Firestore', '~> 6.3.0'
  pod 'Firebase/Messaging', '~> 6.3.0'
  pod 'Firebase/RemoteConfig', '~> 6.3.0'
  pod 'Firebase/Storage', '~> 6.3.0'
  pod 'Firebase/Performance', '~> 6.3.0'

Answer 1

看起来您调用await的方法不是异步的