ios - 'FIRAppNotConfigured'，原因 : 'Failed to get default Firebase Database instance. Must call ` [FIRApp configure ]` (` FirebaseApp. configure()`(Swift 中)

Question

我有开发和生产 Firebase 项目，我正在使用以下方法进行管理，

在我的 AppDelegate didFinishLaunchingWithOptions 中，

// Configure with manual options.
    let secondaryOptions = FirebaseOptions(googleAppID: "1:82121212:ios:212121212121212", gcmSenderID: "872909116998")
    secondaryOptions.bundleID = "com.testApp.test"
    secondaryOptions.apiKey = "AIzasskjkkjhkdhksadhsadaskdhks"
    secondaryOptions.clientID = "82121212-asdsdasdasdasdasdadsdsd.apps.googleusercontent.com"
    secondaryOptions.databaseURL = "https://test-myApp.firebaseio.com"
    secondaryOptions.storageBucket = "test-myApp.appspot.com"

    // Configure an alternative FIRApp.
    FirebaseApp.configure(name: "secondary", options: secondaryOptions)
    guard let secondary = FirebaseApp.app(name: "secondary")
        else { assert(false, "Could not retrieve secondary app") }
    let secondaryDb = Database.database(app: secondary)

在我的另一个 View Controller 中，当从 firebase 数据库获取消息时，我的应用程序崩溃了 “*** 由于未捕获的异常“FIRAppNotConfigured”而终止应用，原因:“无法获取默认 Firebase 数据库实例。必须调用 [FIRApp 配置] (FirebaseApp.configure() 在 Swift 中)在使用 Firebase 数据库之前。'"

我的ChatViewController

class ChatViewController : UIViewController {

var ref : DatabaseReference!
override func viewDidLoad() {
    super.viewDidLoad()
    getChatMessages()
}

@objc func getChatMessages() {

    firebase = Database.database().reference(fromURL: url)
    Auth.auth().signIn(withCustomToken: firBaseAuthToken, completion: { (user, error) in
        if error != nil{
        }
        else
        {
            let userAuthData = user?.additionalUserInfo
            self.uid = (user?.user.uid)!.replacingOccurrences(of: ".", with: "")
            self.successFireBaseAuth(urlString: klUrl)
        }
    })

}

func successFireBaseAuth(urlString : String)
{
    ref = Database.database().reference(withPath: urlString)


    ref.observe(.value, with: { snapshot in
 })
}

Answer 1

从外观上看，您正在访问错误的应用程序实例。

    guard let secondary = FirebaseApp.app(name: "secondary")
        else { assert(false, "Could not retrieve secondary app") }
    let secondaryDb = Database.database(app: secondary)

您自己在 AppDelegate 中的代码，我假设这就是您应该如何获取正确的数据库实例。

但你正在使用

Database.database()

尝试获取消息时。

如果您想使用共享实例，请使用

FirebaseApp.configure(options: secondaryOptions)

配置时