我有以下代码:
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
UIWebView *aWebView;
aWebView = [[UIWebView alloc] initWithFrame:CGRectMake(320, 0, 320, 480)];//init and create the UIWebView
aWebView.autoresizesSubviews = YES;
aWebView.autoresizingMask=(UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth);
//set the web view delegates for the web view to be itself
[aWebView setDelegate:self];
//Set the URL to go to for your UIWebView
NSString *urlAddress = @"www.google.com";
//Create a URL object.
NSURL *url = [NSURL URLWithString:urlAddress];
//URL Requst Object
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
//load the URL into the web view.
[aWebView loadRequest:requestObj];
//add the web view to the content view
[self.view addSubview:aWebView];
}
单击任何单元格时,它应该创建一个 UIWebView 并转到 google.com,但由于某种原因,我收到以下错误:2011-12-04 23:47:56.825 AudStud[906:207] Unknown方案,什么也不做:www.google.com
最佳答案
您的 URL 缺少协议(protocol)部分。它应该是 http://www.google.com
。
关于objective-c - 在 UITableView 中选择单元格时创建 UIWebView,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8378170/