我正在尝试将一些数据发布到 Flask 服务器,其代码如下:
@app.route('/tasks', methods=['POST'])
def create_task():
if not request.json or not 'title' in request.json:
abort(400)
task = {
'title': request.json['title'],
'description': request.json.get('description', ""),
}
return jsonify({'task' : task}), 201
当我运行它时,它工作正常,我可以使用 curl 成功发出 POST 请求,上面的后端有预期的行为,命令行有预期的返回值。但是,我想使用 Swift 向该服务器发帖,但遇到了麻烦。我已经按照详细说明此行为 here 的教程进行操作。特别是,我将代码放在我的 AppDelegate.swift
中,以便在应用程序启动后立即执行。完整代码在发布的链接中,但为了引用,我也在下面发布了它:
func application(application: UIApplication!, didFinishLaunchingWithOptions launchOptions: NSDictionary!) -> Bool {
var request = NSMutableURLRequest(URL: NSURL(string: "http://localhost:4567/login"))
var session = NSURLSession.sharedSession()
request.HTTPMethod = "POST"
var params = ["username":"jameson", "password":"password"] as Dictionary<String, String>
var err: NSError?
request.HTTPBody = NSJSONSerialization.dataWithJSONObject(params, options: nil, error: &err)
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
var task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
println("Response: \(response)")
var strData = NSString(data: data, encoding: NSUTF8StringEncoding)
println("Body: \(strData)")
var err: NSError?
var json = NSJSONSerialization.JSONObjectWithData(data, options: .MutableLeaves, error: &err) as? NSDictionary
// Did the JSONObjectWithData constructor return an error? If so, log the error to the console
if(err != nil) {
println(err!.localizedDescription)
let jsonStr = NSString(data: data, encoding: NSUTF8StringEncoding)
println("Error could not parse JSON: '\(jsonStr)'")
}
else {
// The JSONObjectWithData constructor didn't return an error. But, we should still
// check and make sure that json has a value using optional binding.
if let parseJSON = json {
// Okay, the parsedJSON is here, let's get the value for 'success' out of it
var success = parseJSON["success"] as? Int
println("Succes: \(success)")
}
else {
// Woa, okay the json object was nil, something went worng. Maybe the server isn't running?
let jsonStr = NSString(data: data, encoding: NSUTF8StringEncoding)
println("Error could not parse JSON: \(jsonStr)")
}
}
})
task.resume()
return true
}
但是,当我启动这个应用程序时,我的 xcode 中记录了以下内容
Response: <NSHTTPURLResponse: 0x7fc4dae218a0> { URL: http://localhost:5000/task } { status code: 404, headers {
"Content-Length" = 26;
"Content-Type" = "application/json";
Date = "Tue, 07 Oct 2014 19:22:57 GMT";
Server = "Werkzeug/0.9.6 Python/2.7.5";
} }
Body: {
"error": "Not found"
}
Succes: nil
我一直在处理这个问题并修改输入,后端似乎很好,但我想知道这个前端有什么问题,不幸的是,Swift 文档目前在这一点上还没有实际意义并且似乎是目前唯一适用于 RESTful API 调用的解决方案。
最佳答案
你的 flask 路由是 '/tasks'
并且你正试图发布到 http://localhost:5000/task
。这是错字,还是您是复数失败的受害者?
关于python - 如何让 Swift HTTP POST 命中 Flask 服务器?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26244109/