自 Android 开发者 recommend要使用 HttpURLConnection
类,我想知道是否有人可以为我提供一个很好的示例,说明如何通过 POST 将位图"file"(实际上是内存中的流)发送到 Apache HTTP 服务器。我对 cookie 或身份验证或任何复杂的东西不感兴趣,但我只想拥有一个可靠且符合逻辑的实现。我在这里看到的所有示例看起来更像是“让我们试试这个,也许它会起作用”。
现在,我有这个代码:
URL url;
HttpURLConnection urlConnection = null;
try {
url = new URL("http://example.com/server.cgi");
urlConnection = (HttpURLConnection) url.openConnection();
} catch (Exception e) {
this.showDialog(getApplicationContext(), e.getMessage());
}
finally {
if (urlConnection != null)
{
urlConnection.disconnect();
}
}
其中 showDialog 应该只显示一个 AlertDialog
(如果 URL 无效?)。
现在,假设我生成了一个像这样的位图: Bitmap image = this.getBitmap()
在从 View
派生的控件中,我想通过它发送它邮政。实现这样的事情的正确程序是什么?我需要使用哪些类?我可以像在 this example 中那样使用 HttpPost
吗? ?如果是这样,我将如何为我的位图构造 InputStreamEntity
?我会发现要求首先将位图存储在设备上的文件中是令人反感的。
我还应该提到,我确实需要将原始位图的每个未更改的像素发送到服务器,所以我无法将其转换为 JPEG。
最佳答案
我不知道为什么 HttpURLConnection
类不提供任何发送文件的方法,而无需手动编写文件包装器。这是我最终做的,但如果有人知道更好的解决方案,请告诉我。
输入数据:
Bitmap bitmap = myView.getBitmap();
静态的东西:
String attachmentName = "bitmap";
String attachmentFileName = "bitmap.bmp";
String crlf = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
设置请求:
HttpURLConnection httpUrlConnection = null;
URL url = new URL("http://example.com/server.cgi");
httpUrlConnection = (HttpURLConnection) url.openConnection();
httpUrlConnection.setUseCaches(false);
httpUrlConnection.setDoOutput(true);
httpUrlConnection.setRequestMethod("POST");
httpUrlConnection.setRequestProperty("Connection", "Keep-Alive");
httpUrlConnection.setRequestProperty("Cache-Control", "no-cache");
httpUrlConnection.setRequestProperty(
"Content-Type", "multipart/form-data;boundary=" + this.boundary);
启动内容包装器:
DataOutputStream request = new DataOutputStream(
httpUrlConnection.getOutputStream());
request.writeBytes(this.twoHyphens + this.boundary + this.crlf);
request.writeBytes("Content-Disposition: form-data; name=\"" +
this.attachmentName + "\";filename=\"" +
this.attachmentFileName + "\"" + this.crlf);
request.writeBytes(this.crlf);
转换 Bitmap
至ByteBuffer
:
//I want to send only 8 bit black & white bitmaps
byte[] pixels = new byte[bitmap.getWidth() * bitmap.getHeight()];
for (int i = 0; i < bitmap.getWidth(); ++i) {
for (int j = 0; j < bitmap.getHeight(); ++j) {
//we're interested only in the MSB of the first byte,
//since the other 3 bytes are identical for B&W images
pixels[i + j] = (byte) ((bitmap.getPixel(i, j) & 0x80) >> 7);
}
}
request.write(pixels);
结束内容包装:
request.writeBytes(this.crlf);
request.writeBytes(this.twoHyphens + this.boundary +
this.twoHyphens + this.crlf);
刷新输出缓冲区:
request.flush();
request.close();
得到响应:
InputStream responseStream = new
BufferedInputStream(httpUrlConnection.getInputStream());
BufferedReader responseStreamReader =
new BufferedReader(new InputStreamReader(responseStream));
String line = "";
StringBuilder stringBuilder = new StringBuilder();
while ((line = responseStreamReader.readLine()) != null) {
stringBuilder.append(line).append("\n");
}
responseStreamReader.close();
String response = stringBuilder.toString();
关闭响应流:
responseStream.close();
关闭连接:
httpUrlConnection.disconnect();
PS:当然,我必须将请求包装在 private class AsyncUploadBitmaps extends AsyncTask<Bitmap, Void, String>
中。 ,为了让Android平台开心,因为它不喜欢在主线程上有网络请求。
关于android - 使用带有 HttpURLConnection 的 POST 发送文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11766878/