iphone - 在同一 View Controller 中进行一次、两次和三次点击操作

标签 iphone ios objective-c uigesturerecognizer

我正在使用 UITapGestureRecognizer 并尝试让不同的点击在同一个 ViewController 上工作,但通过单击点击失败

我试图找到解决方案,但无法将其集成到我的测试代码中。我非常感谢对此的帮助,以便我可以从中学习。

这是我用来测试的代码:

.h 文件:

@interface ViewController : UIViewController <UIGestureRecognizerDelegate>

.m 文件:

@interface ViewController ()

@property (nonatomic, strong) UITapGestureRecognizer *tapGestureRecognizer3;
@property (nonatomic, strong) UITapGestureRecognizer *tapGestureRecognizer2;
@property (nonatomic, strong) UITapGestureRecognizer *tapGestureRecognizer1;

@end

@implementation ViewController

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer {

return YES;

}

- (void)viewDidLoad
{
[super viewDidLoad];


self.view.backgroundColor = [UIColor greenColor];

// Create Tap Gesture Recognizer

//==1
self.tapGestureRecognizer1 = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(handle1Taps:)];
self.tapGestureRecognizer1.numberOfTouchesRequired = 1;
self.tapGestureRecognizer1.numberOfTapsRequired = 1;

//==2
self.tapGestureRecognizer2 = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(handle2Taps:)];
self.tapGestureRecognizer2.numberOfTouchesRequired = 1;
self.tapGestureRecognizer3.numberOfTapsRequired = 2;

//== #3
self.tapGestureRecognizer3 = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(handle3Taps:)];
self.tapGestureRecognizer3.numberOfTouchesRequired = 1;
self.tapGestureRecognizer3.numberOfTapsRequired = 3;


[self.tapGestureRecognizer1 requireGestureRecognizerToFail:self.tapGestureRecognizer2];
[self.tapGestureRecognizer1 requireGestureRecognizerToFail:self.tapGestureRecognizer3];
[self.tapGestureRecognizer2 requireGestureRecognizerToFail:self.tapGestureRecognizer3];

// Add gestures
[self.view addGestureRecognizer:self.tapGestureRecognizer1];
[self.view addGestureRecognizer:self.tapGestureRecognizer2];
[self.view addGestureRecognizer:self.tapGestureRecognizer3];

}

- (void)handle1Taps:(UITapGestureRecognizer *)paramSender {
NSLog(@"handle-1-Taps");

NSUInteger touchCounter = 0;

for (touchCounter = 0; touchCounter < paramSender.numberOfTouchesRequired; touchCounter++) {

    CGPoint touchPoint = [paramSender locationOfTouch:touchCounter inView:paramSender.view];

    NSLog(@">>1 x TAP<<");


}

}

- (void)handle2Taps:(UITapGestureRecognizer *)paramSender {
NSLog(@"handle-2-Taps");
NSUInteger touchCounter = 0;

for (touchCounter = 0; touchCounter < paramSender.numberOfTouchesRequired; touchCounter++) {

    CGPoint touchPoint = [paramSender locationOfTouch:touchCounter inView:paramSender.view];

    NSLog(@">>2 x TAP<<");


}

}

- (void)handle3Taps:(UITapGestureRecognizer *)paramSender {
NSLog(@"handle-3-Taps");
NSUInteger touchCounter = 0;

for (touchCounter = 0; touchCounter < paramSender.numberOfTouchesRequired; touchCounter++) {

    CGPoint touchPoint = [paramSender locationOfTouch:touchCounter inView:paramSender.view];

    NSLog(@">>3 x TAP<<");


}

}

@end

以下是第一次与 VC 交互的结果:

 - 1 x tap = >>2 x TAP<<
 - 2 x tap = >>2 x TAP<<
 - 3 x tap = >>3 x TAP<<

最佳答案

嘿 检查一下: 最后一行是错误的。

self.tapGestureRecognizer2 = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(handle2Taps:)];
self.tapGestureRecognizer2.numberOfTouchesRequired = 1;
self.tapGestureRecognizer3.numberOfTapsRequired = 2;

应该是

self.tapGestureRecognizer2.numberOfTapsRequired = 2;

希望这对您有帮助。

关于iphone - 在同一 View Controller 中进行一次、两次和三次点击操作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18589834/

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