iphone - 无法获取 CALayer iOS 的正确位置

Question

我正在 iOS 中使用 CALayer，在 myView 中添加了一个子图层，并尝试通过触摸开始获取触摸事件，但我收到的触摸事件不在我绘制图层的位置，如果有问题，请帮助我纠正它.

UIView *myView = [[UIView alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
myView.backgroundColor = [UIColor whiteColor];

magicButton_ = [UIButton buttonWithType:UIButtonTypeRoundedRect];
magicButton_.frame = CGRectMake(10., 10., 300., 44.);
[magicButton_ setTitle:@"Invoke Magic!" forState:UIControlStateNormal];
[magicButton_ addTarget:self action:@selector(toggleMoney:) forControlEvents:UIControlEventTouchUpInside];
[myView addSubview:magicButton_];

simpleLayer_ = [[CALayer alloc]init];


simpleLayer_.bounds = CGRectMake(0., 0., 150., 20.);
simpleLayer_.position = CGPointMake((myView.center.x),(myView.center.y));
simpleLayer_.name = @"redlayer";
simpleLayer_.delegate = self;
simpleLayer_.backgroundColor = [[UIColor redColor]CGColor];
[myView.layer addSublayer:simpleLayer_];
self.view = myView;

-(void)touchesBegan:(NSSet*)touches withEvent:(UIEvent*)event {
    CGPoint location = [[touches anyObject] locationInView:self.view];
    CALayer *hitLayer = [self.view.layer hitTest:[self.view convertPoint:location             fromView:nil]];

    NSLog(@"Location %f  %f",location.x,location.y);
    [self displayInfo:hitLayer.name];
}


-(void)displayInfo:(NSString *)nameOfLayer
{
   NSLog(@"%@",nameOfLayer);
}

2013-10-14 13:13:37.374 MyLayerProj[1750:11303] (null)
2013-10-14 13:13:38.468 MyLayerProj[1750:11303] Location 87.000000  269.000000
2013-10-14 13:13:38.469 MyLayerProj[1750:11303] (null)
2013-10-14 13:13:39.239 MyLayerProj[1750:11303] Location 112.000000  278.000000
2013-10-14 13:13:39.240 MyLayerProj[1750:11303] redlayer
2013-10-14 13:13:40.479 MyLayerProj[1750:11303] Location 119.000000  278.000000   

我还包含了运行代码时收到的日志。

Answer 1

调用 -[CALayer hitTest] 时的 [self.view ConvertPoint:location fromView:nil] 表示“将 location 从窗口的坐标空间到self.view的坐标空间。

但是，location 已经在 View 的坐标空间中，因为您是通过将 self.view 传递给 -[UITouch locationInView: ]。