所以我在 [2] 中有一个按钮,它通过导航 Controller 推送到 [3],这样我就可以使用工具栏中的“后退”按钮返回到 [2]。这一切都很好。
在 [4] 中我也有一个按钮,我希望它转到 [3]。但它也应该通过导航 Controller ,这样当我按下“返回”时,我可以再次返回到 [2]。
所以实际上我希望 [4] 上的按钮像 [ 1 ][ 2 ][ 3 ] 这样我就可以从 [3] 返回到 [2]
@IBAction func showKaart(sender: AnyObject) {
performSegueWithIdentifier("menuToKaart", sender: sender)
}
最佳答案
如果我理解你的问题,我相信试试吧。
请注意您的 Root View Controller 是 vc[2]
,好吗?
您从 vc[2]
> vc[3]
推送,然后按返回并返回到 vc[2]
,没关系!
您从 vc[4]
> vc[3]
推送,然后按返回并返回到 vc[4]
,但您需要返回到vc[2]
?
对于此逻辑,您可以为 vc[3]
创建自定义行为
对于你的 vc[3]
我这样做是为了控制行为。
class ViewController3:UIViewController{
var backToRoot:Bool = false;
override func viewDidLoad() {
super.viewDidLoad();
self.hideAndAddNewBackButton();
}
private func hideAndAddNewBackButton(){
self.navigationItem.hidesBackButton = true
let newBackButton = UIBarButtonItem(title: "Back", style: UIBarButtonItemStyle.Plain, target: self, action: "back:")
self.navigationItem.leftBarButtonItem = newBackButton;
}
func back(sender: UIBarButtonItem) {
if backToRoot{
self.navigationController?.popToRootViewControllerAnimated(true);
}else{
self.navigationController?.popViewControllerAnimated(true)
}
}
func needBackToRoot(){
backToRoot = true;
}
}
现在在 vc[4]
中,我认为您可以修改 vc[3]
的后退按钮行为
我介意用两种方式处理你的 vc[4]
首先使用 performSegue。
class ViewController4PerfomSegue:UIViewController{
@IBAction func pressButtonToPushViewController3(sender:AnyObject?){
self.performSegueWithIdentifier("showViewController3", sender: nil);
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if let viewController3 = segue.destinationViewController as? ViewController3{
viewController3.needBackToRoot();
}
}
}
其次在导航 View Controller 中使用推送手册
class ViewController4Push:UIViewController{
@IBAction func pressButtonToPushViewController3(sender:AnyObject?){
let viewController3 = ViewController3(nibName: "ViewController3", bundle: nil);
viewController3.needBackToRoot();
self.navigationController?.pushViewController(viewController3, animated: true);
}
}
编辑:从 Storyboard实例化的新方法
class ViewController4Push:UIViewController{
@IBAction func pressButtonToPushViewController3(sender:AnyObject?){
if let viewController3 = storyboard!.instantiateViewControllerWithIdentifier("ViewController3") as? ViewController3{
viewController3.needBackToRoot();
self.navigationController?.pushViewController(viewController3, animated: true);
}
}
}
编辑:在呈现新 View 时删除
class ViewController4Push:UIViewController, UINavigationControllerDelegate{
@IBAction func pressButtonToPushViewController3(sender:AnyObject?){
if let viewController3 = storyboard!.instantiateViewControllerWithIdentifier("ViewController3") as? ViewController3{
viewController3.needBackToRoot();
self.navigationController?.delegate = self;
self.navigationController?.pushViewController(viewController3, animated: true);
}
}
func navigationController(navigationController: UINavigationController, didShowViewController viewController: UIViewController, animated: Bool) {
self.navigationController?.delegate = nil;
self.dismissViewControllerAnimated(false, completion: nil);
//or self.removeFromParentViewController();
}
}
如果我理解了问题,希望对你有帮助
编辑:和思南聊天后我们用简单的方法解决了,强制返回应用的根元素即可
class ViewCustomController:UIViewController{
override func viewDidLoad() {
super.viewDidLoad();
self.hideAndAddNewBackButton();
}
private func hideAndAddNewBackButton(){
self.navigationItem.hidesBackButton = true
let newBackButton = UIBarButtonItem(title: "Back", style: UIBarButtonItemStyle.Plain, target: self, action: "back:")
self.navigationItem.leftBarButtonItem = newBackButton;
}
func back(sender: UIBarButtonItem) {
if let viewControllerRoot = storyboard!.instantiateViewControllerWithIdentifier("ViewControllerRoot") as? ViewControllerRoot{
self.navigationController?.pushViewController(viewController2, animated: true);
}
}
}
关于ios - 通过导航 Controller 继续,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32397752/