ios - 两个 NSDate 之间的周末数

Question

假设我们使用公历系统，计算两个 NSDate 对象之间的周末数的最佳方法是什么？

我目前的方法是计算两个 NSDate 之间的天数，然后除以 7，然后用 floor() 计算结果。这给了我周数，结果是周末数。因为如果一周尚未结束(除法还有余数)，我们将floor计算结果，它会忽略这一点，只考虑过去的整周。

如有任何改进和稳健性建议，我们将不胜感激。

Answer 1

像这样尝试，代码的描述在注释中:-

//Assuming this is your dates where you need to determine the weekend in between two dates
NSString *strDate1=@"10-01-2014";
NSString *strDate2=@"19-01-2014";
NSDateFormatter *format=[[NSDateFormatter alloc]init];
[format setDateFormat:@"dd-MM-yyyy"];
NSDate *dt1=[format dateFromString:strDate1];
NSDate *dt2=[format dateFromString:strDate2];

//Now finding the days between two dates
NSUInteger units = NSYearCalendarUnit|NSMonthCalendarUnit|NSDayCalendarUnit|NSWeekdayCalendarUnit;
NSCalendar *cal = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
NSDateComponents *com=[cal components:units fromDate:dt1 toDate:dt2 options:0];
NSInteger day1=[com day];
int i=0;
int j=0;


//Now calculating how many weekends(Sat, Sun) are there in the total number of days.
for(i=0; i<=day1; i++)
{
    com=[[NSDateComponents alloc]init];
    [com setDay:i];
    NSDate *newDate = [[NSCalendar currentCalendar]
                       dateByAddingComponents:com
                       toDate:dt1 options:0];
    [format setDateFormat:@"EEE"];
    NSString *satSun=[format stringFromDate:newDate];
    if ([satSun isEqualToString:@"Sat"] || [satSun isEqualToString:@"Sun"])
    {
        j++;

    }
}
        NSLog(@"Total number of weekends found= %d",j);