ios - 基于C#程序的Swift电话词生成器实现

Question

我目前正在尝试实现电话词生成器。我在网上四处寻找我可以使用的东西，这就是我找到的。

我在 C# 中找到了这个实现:

public static void printPhoneWords(int[] number) {
     char[] output = new char[number.length];
     printWordsUtil(number,0,output);
}

static String[] phoneKeys= new String[]{"0", "1", "ABC", "DEF", "GHI", "JKL",
               "MNO", "PQRS", "TUV", "WXYZ"};
private static void printWordsUtil(int[] number, int curDigIndex, char[] output) {
    // Base case, if current output word is done
    if (curDigIndex == output.length) {
        System.out.print(String.valueOf(output) + " "); 
        return;
    }
  // Try all 3-4 possible characters for the current digit in number[]
  // and recurse for the remaining digits

char curPhoneKey[] = phoneKeys[number[curDigIndex]].toCharArray();
for (int i = 0; i< curPhoneKey.length ; i++) {
    output[curDigIndex] = curPhoneKey[i];
    printWordsUtil(number, curDigIndex+1, output);
    if (number[curDigIndex] <= 1) // for 0 or 1
        return;
    }
}

public static void main(String[] args) {
    int number[] = {2, 3, 4};
    printPhoneWords(number);
    System.out.println();
}

现在，我尝试在 Swift 中实现它，但我遇到了一些问题..

var pinDict = [2:"abc", 3:"def", 4:"ghi", 5:"jkl", 6:"mno", 7:"pqrs", 8:"tuv", 9:"wxyz"]


func printWordsUtil(number: [Int], curDigIndex: Int, output: Array<Character>) {

    var curPhoneKey:Array<Character> = []

    curPhoneKey = pinDict[number[curDigIndex]]

    for var i = 0; i < curPhoneKey.count; i++ {
        output[curDigIndex] = pinDict[i]
        printWordsUtil(number, curDigIndex+1, output)
        if(number[curDigIndex] <= 1) {
            return
        }
    }
}
func printPhoneWords(number: [Int]) {
    var output:Array<Character> = []
    printWordsUtil(number,0,output)
}
func main() {
    var number = [2, 2, 7, 3]
    printPhoneWords(number)
}

我在这里遇到错误:

• curPhoneKey = pinDict[number[curDigIndex]]//'(Int, String)'不可转换为 'Array<Character>'不确定如何解决这个问题...
• output[curDigIndex] = pinDict[i]//'@lvalue $T8'与“字符”不相同

关于如何让这个实现在 Swift 中工作有什么想法吗？

好的，现在我有这个:

comparisonArray.append(dictionary[a!])
comparisonArray.append(dictionary[b!])
comparisonArray.append(dictionary[c!])
comparisonArray.append(dictionary[d!])
func combos<T>(var array: Array<T>, k: Int) -> Array<Array<T>> {
    if k == 0 { return [[]] } if array.isEmpty { return [] }
    let head = [array[0]]
    let subcombos = combos(array, k - 1)
    var ret = subcombos.map {head + $0} 
    array.removeAtIndex(0)
    ret += combos(array, k) 
    return ret 
}
combos(comparisonArray, 4)

比较数组是["ABC, "DEF", "DEF, "PQRS"] .现在，如何单独排列每个组合中的每个字母而不是排列元素，所以它看起来像这样？ ["A", "D", "D", "P"] , ["B", "D", "D", "P"] ？谢谢!

Answer 1

您将需要此字符串扩展名:

extension String {
    subscript (index:Int) -> String { return String(Array(self)[index]) }
}

首先让我们将 Int 数组转换为字符串数组

func intArrayToStringArray(number: [Int]) -> [String] {
    if number.isEmpty { return [] }
    let keyboard = ["0","1","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"]        var result:[String] = []
    for i in 0..<number.count {
        result.append(keyboard[number[i]])
    }
    return result
}

let firstStep = intArrayToStringArray([2,2,7,3])  //  ["abc", "abc", "pqrs", "def"] 

然后我们需要为每个数字嵌套一个循环并使用它们的索引组合选择字母，使用字符串插值连接它们并将其附加到输出数组。

func secontStep(input:[String]) -> [String] {
    var output:[String] = []
    for w in 0..<countElements(input[0]) {
        for x in 0..<countElements(input[1]) {
            for y in 0..<countElements(input[2]){
                for z in 0..<countElements(input[3]){
                    output.append("\(input[0][w])\(input[1][x])\(input[2][y])\(input[3][z)")
                }
            }
        }
    }
    return output
}
let wordsArray = secontStep(firstStep) // ["aapd", "aape", "aapf", "aaqd", "aaqe", "aaqf", "aard", "aare", "aarf", "aasd", "aase", "aasf", "abpd", "abpe", "abpf", "abqd", "abqe", "abqf", "abrd", "abre", "abrf", "absd", "abse", "absf", "acpd", "acpe", "acpf", "acqd", "acqe", "acqf", "acrd", "acre", "acrf", "acsd", "acse", "acsf", "bapd", "bape", "bapf", "baqd", "baqe", "baqf", "bard", "bare", "barf", "basd", "base", "basf", "bbpd", "bbpe", "bbpf", "bbqd", "bbqe", "bbqf", "bbrd", "bbre", "bbrf", "bbsd", "bbse", "bbsf", "bcpd", "bcpe", "bcpf", "bcqd", "bcqe", "bcqf", "bcrd", "bcre", "bcrf", "bcsd", "bcse", "bcsf", "capd", "cape", "capf", "caqd", "caqe", "caqf", "card", "care", …, "cbqe", "cbqf", "cbrd", "cbre", "cbrf", "cbsd", "cbse", "cbsf", "ccpd", "ccpe", "ccpf", "ccqd", "ccqe", "ccqf", "ccrd", "ccre", "ccrf", "ccsd", "ccse", "ccsf"]

相反的是这样的:

func stringToArray(var number: String) -> [Int] {
    if number == "" { return [] }
    number = number.lowercaseString
    var result:[Int] = []
    for i in 0..<countElements(number) {
        if number[i] == "0" { result.append(0) }
        if number[i] == "1" { result.append(1) }
        if number[i] == "2" || number[i] == "a" || number[i] == "b" || number[i] == "c"                     { result.append(2) }
        if number[i] == "3" || number[i] == "d" || number[i] == "e" || number[i] == "f"                     { result.append(3) }
        if number[i] == "4" || number[i] == "g" || number[i] == "h" || number[i] == "i"                     { result.append(4) }
        if number[i] == "5" || number[i] == "j" || number[i] == "k" || number[i] == "l"                     { result.append(5) }
        if number[i] == "6" || number[i] == "m" || number[i] == "n" || number[i] == "o"                     { result.append(6) }
        if number[i] == "7" || number[i] == "p" || number[i] == "q" || number[i] == "r" || number[i] == "s" { result.append(7) }
        if number[i] == "8" || number[i] == "t" || number[i] == "u" || number[i] == "v"                     { result.append(8) }
        if number[i] == "9" || number[i] == "w" || number[i] == "x" || number[i] == "y" || number[i] == "z" { result.append(9) }
    }
    return result
}
stringToArray("1800HELLO")  // [1, 8, 0, 0, 4, 3, 5, 5, 6]
stringToArray("1800hello")  // [1, 8, 0, 0, 4, 3, 5, 5, 6]