ios - 回到IOS上未访问的页面

Question

我不熟悉IOS开发，所以可能是一个简单的问题:用户是否有可能按下顶部的“后退”按钮，并转到(到目前为止)未访问的页面？ 这是图片:

在窗口“1”上，用户按下按钮，下一个窗口是“2”。但是在这里，如果用户按下“后退”按钮，就会转到页面“3”(到目前为止从未打开过)？

谢谢

Answer 1

您可以通过在第二个 View Controller 中创建一个新按钮来简单地重新定义后退按钮，如下所示:

- (void)viewDidLoad {
    [super viewDidLoad];

    UIButton *backButton = [[UIButton alloc] initWithFrame: CGRectMake(0, 0, 60.0f, 30.0f)];
    [backButton setTitle:@"Back" forState:UIControlStateNormal];
    [backButton setTitleColor:self.view.tintColor forState:UIControlStateNormal];
    [backButton addTarget:self action:@selector(pushToNextController) forControlEvents:UIControlEventTouchUpInside];
    UIBarButtonItem *backButtonItem = [[UIBarButtonItem alloc] initWithCustomView:backButton];
    self.navigationItem.leftBarButtonItem = backButtonItem;
}

- (void)pushToNextController {
    UIViewController *thirdViewController = [self.storyboard instantiateViewControllerWithIdentifier:@"thirdViewController"];
    [self.navigationController pushViewController:thirdViewController animated:YES];
}