我正在尝试在 TableView 中显示 JSON 数据，但收到一条错误消息:“无法将类型‘[String : JSON]’的值转换为预期的参数类型‘String’。有什么想法吗？提前致谢. 另外，我是否打算以正确的方式填充表格 View ？我正在使用 SwiftyJSON。
var TableData:Array< String > = Array < String >()
override func viewDidLoad() {
super.viewDidLoad()
splitViewController!.preferredDisplayMode = UISplitViewControllerDisplayMode.AllVisible
UINavigationBar.appearance().barTintColor = UIColor(red: 52.0/255.0, green: 170.0/255.0, blue: 220.0/255.0, alpha: 1.0)
UINavigationBar.appearance().tintColor = UIColor.whiteColor()
UINavigationBar.appearance().titleTextAttributes = [NSForegroundColorAttributeName : UIColor.whiteColor()]
//JSON
let url = NSURL(string:"https://www.kimonolabs.com/api/7flcy3qm?apikey=gNq3hB1j0NtBdAvXJLEFx8JaqtDG8y6Y")!
let session = NSURLSession.sharedSession()
let task = session.dataTaskWithURL(url) { (data, response, error) -> Void in
if error != nil {
print(error)
} else {
if let _ = data {
do {
let jsonString = try NSString.init(contentsOfURL: url, encoding: NSUTF8StringEncoding)
// Create JSON object from data
let json = JSON(data: jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)!)
// Check if array for key "collection2" exists
if let collection2 = json["results"]["collection2"].array {
// Create JSON array from it and loop for each object
for (_, subJson):(String, JSON) in JSON(collection2) {
// Check if dictionary for key "Event" exists
if let event = subJson["Event"].dictionary {
print(event)
}
// Check if string for key "Hasta" exists
if let hasta = subJson["Hasta"].string {
print(hasta)
}
// Check if string for key "Location" exists
if let location = subJson["Location"].string {
print(location)
}
}
}
} catch {
print("In catch block")
}
}
}
}
task.resume()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
// MARK: - Table view data source
override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
// #warning Incomplete implementation, return the number of sections
return 1
}
override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
// #warning Incomplete implementation, return the number of rows
return self.TableData.count
}
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath)
cell.textLabel?.text = self.TableData[indexPath.row]
return cell
}
}
最佳答案
我修改了你的代码
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
var tableData = [String]()
override func viewDidLoad() {
super.viewDidLoad()
splitViewController!.preferredDisplayMode = UISplitViewControllerDisplayMode.AllVisible
UINavigationBar.appearance().barTintColor = UIColor(red: 52.0/255.0, green: 170.0/255.0, blue: 220.0/255.0, alpha: 1.0)
UINavigationBar.appearance().tintColor = UIColor.whiteColor()
UINavigationBar.appearance().titleTextAttributes = [NSForegroundColorAttributeName : UIColor.whiteColor()]
//JSON
let url = "https://www.kimonolabs.com/api/7flcy3qm?apikey=gNq3hB1j0NtBdAvXJLEFx8JaqtDG8y6Y"
makeRequest("GET", api: url, params: nil, values: nil) { (dic) -> Void in
if let resultsDic = dic.valueForKey("results") as? NSDictionary
{
if let collection2 = resultsDic.valueForKey("collection2") as? NSArray
{
//do the for loop and get values
}
}
}
}
// MARK: - Table view data source
override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
// #warning Incomplete implementation, return the number of sections
return 1
}
override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
// #warning Incomplete implementation, return the number of rows
return self.tableData .count
}
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath)
cell.textLabel?.text = self.tableData [indexPath.row]
return cell
}
typealias JSON = AnyObject
typealias JSONDictionary = Dictionary<String, JSON>
typealias JSONArray = Array<JSON>
func makeRequest(method : String , api : String , params : Dictionary<String , AnyObject>? , values : Dictionary<String , String>? , completionHandler : (NSDictionary->Void)?)
{
var request = NSMutableURLRequest(URL: NSURL(string:api)!)
var session = NSURLSession.sharedSession()
request.HTTPMethod = method
// NSJSONSerialization.JSONObjectWithData(<#data: NSData#>, options: <#NSJSONReadingOptions#>, error: <#NSErrorPointer#>)
// var err: NSError?
if let myValues = values
{
for keyValue in myValues
{
request.addValue(keyValue.1, forHTTPHeaderField: keyValue.0)
}
}
//var params = ["emailToFollow":self.user!.email, "follow" : follow.description] as Dictionary<String, String>
if let myParams = params
{
// request.HTTPBody = NSJSONSerialization.dataWithJSONObject(myParams, options: nil, error: &err)
do
{
try request.HTTPBody = NSJSONSerialization.dataWithJSONObject(myParams, options: [])
}
catch
{
print("error \n")
}
}
//var httpRes = HttpPostREsult.FAIL
let task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
//var strData = NSString(data: data!, encoding: NSUTF8StringEncoding)
// var err: NSError?
do
{
let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .MutableLeaves) as? NSDictionary
print("request sent \n")
if let parseJSON = json
{
if let myComplitionHandler = completionHandler
{
myComplitionHandler(parseJSON)
}
}
else
{
// the json object was nil, something went worng. Maybe the server isn't running?
let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)
print("Error could not parse JSON: \(jsonStr) \n")
}
}
catch let error as NSError
{
print("error \(error.localizedDescription)")
let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)
print("error \(jsonStr)")
}
})
task.resume()
}
变化: 1 - HttpRequest 函数，它向 url 发出请求并“返回”一个接受字典的 block ，这是一种更简洁的请求方式，它还有两个功能(您可以发送正文和 header ) 2 - 改变了你解析信息的方式
希望这有帮助! :D
关于ios - JSON Swift 填充 TableView 错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33324922/