ios - 如何在字符串列中使用 where 键数组？

Question

我有一个名称数组和一个字符串类型的列，我正在尝试获取信息。当我对 where 键中的每个值使用 for 循环时，我得到很多相同的信息，所以说有 5 个名字，我试图获取速率(一个整数)我会得到 100 个值而不是只需 5 个。

var name = ["Dog", "Cat", "Monkey"]
let query = PFQuery(className: "Animals")
    query.whereKey(not sure what to put since it is an array)
    query.findObjectsInBackgroundWithBlock { (objects: [PFObject]?, error: NSError?) in
        if(error == nil){
            for object in objects!{


                        if let rating = object["rate"] as? Int{
                            self.rater.append(rating)
                            print("rating \(self.rater)") //There are like 75-100 values
                        }
            }
        }else{
            print(error)
            }
        }

Answer 1

我不太了解Parse，但是有这个方法-whereKey:containedIn:它需要一个数组。那对你不起作用吗？ (抱歉，我没有找到 Swift 文档)

文档说:

-whereKey:containedIn:

Add a constraint to the query that requires a particular key’s object to be contained in the provided array.

Declaration OBJECTIVE-C

- (nonnull instancetype)whereKey:(nonnull NSString *)key
                 containedIn:(nonnull NSArray *)array;

Parameters:

-key The key to be constrained.

-array The possible values for the key’s object.