html - 快速解析 HTML

Question

谁能帮我解决这个问题:

我有一个这样格式化的 HTTP 页面:

<ul class="ms-spbTree" id="_ul">
    <li id="XXX\$username">Person0
        <ul id="XXX\$username_ul">
            <li id="XXX\$username">Person1
                <ul id="XXX\$username_ul"></ul>
            </li>
            <li id="XXX\$username">Person2
                <ul id="XXX\$username_ul"></ul>
            </li>
            <li id="XXX\$username">Person3
                <ul id="XXX\$username_ul"></ul>
            </li>
            <li id="XXX\$username">Person4
                <ul id="XXX\$username_ul">
                    <li id="XXX\$username">Person5
                        <ul id="XXX\$username_ul"></ul>
                    </li>
                    <li id="XXX\$username">Person6
                        <ul id="XXX\$username_ul"></ul>
                    </li>
                    <li id="XXX\$username">Person7
                        <ul id="XXX\$username_ul"></ul>
                    </li>
                </ul>
            </li>
            <li id="XXX\$username">Person8
                <ul id="XXX\$username_ul"></ul>
            </li>
        </ul>
    </li>
</ul>

我的职能是:

func loadTutorial(webString: NSString)
{
    var data : NSData = webString.dataUsingEncoding(NSUTF8StringEncoding)!

    var tutorialsParser = TFHpple(HTMLData: data)
    var tutorialsXPathString = "//ul/li"
    var tutorialNodes = tutorialsParser.searchWithXPathQuery(tutorialsXPathString) as NSArray
    if(tutorialNodes.count == 0)
    {
        println("empty here")
    }
    else
    {
        for element in tutorialNodes
        {
            var elementTwo: TFHppleElement = element as TFHppleElement
         //   var tutorial = Tutorial()
            println("\(elementTwo.firstChild.content)")

       //     println(elementTwo.raw)

            let userscanner = NSScanner(string:elementTwo.raw)
            var userscanned: NSString?

            if userscanner.scanUpToString("li id=\"", intoString:nil){
                userscanner.scanString("li id=\"", intoString:nil)
                if userscanner.scanUpToString("\">", intoString:&userscanned) {
                    let newResult: String = userscanned as String

                    println("NewResultValue: \(newResult)")
                }
            }
        }
    }
}

但我得到的是以下列表:

Person0
Person1
Person2
Person3
Person4
Person5
Person6
Person7
Person8

我只想检索

Person0
Person1
Person2
Person3
Person4
Person8

或者我列出来，这样我就知道 Person5、6 和 7 有 Person4 作为经理。

我尝试过

var tutorialsXPathString = "//ul[not(contains(@style, 'style=\"display: none;\"'))/li"

因为所有子人(5,6,7)的标签中都有这个，但它不起作用:(

如有任何帮助，我们将不胜感激。

Answer 1

一些想法:

1. 使用 // 表示“在 HTML 中任何地方查找此内容”。如果您想控制要考虑的级别，只需使用 / 并从文档的根目录开始执行即可。例如，要获得第二级，而不是第一级或第三级，您可以执行以下操作:

   let tutorialsParser = TFHpple(HTMLData: data)
   let tutorialsXPathString = "/html/body/ul/li/ul/li"
   if let tutorialNodes = tutorialsParser.searchWithXPathQuery(tutorialsXPathString) as? [TFHppleElement] {
       for element in tutorialNodes {
           let content = element.firstChild.content.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
           let identifier = element.attributes["id"] as String
           println("id = \(identifier); content = \(content)")
       }
   }
   

2. 注意，我不确定您为什么使用扫描仪，但如果您想要元素的属性，可以使用 attributes 方法。

   <

3. 我还将 tutorialNodes 定义为 TFHppleElement 对象数组，这稍微简化了 for 循环。

4. 如果您想要顶级 /ul/li 后跟第二级，而不是第三级，您可以执行以下操作:

   let tutorialsParser = TFHpple(HTMLData: data)
   let tutorialsXPathString = "/html/body/ul/li"
   if let tutorialNodes = tutorialsParser.searchWithXPathQuery(tutorialsXPathString) as? [TFHppleElement] {
       for element in tutorialNodes {
           let content = element.firstChild.content.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
           let identifier = element.attributes["id"] as String
           println("id = \(identifier); content = \(content)")
   
           if let ul = element.childrenWithTagName("ul") as? [TFHppleElement] {
               if let li = ul.first?.childrenWithTagName("li") as? [TFHppleElement] {
                   for element in li {
                       let content = element.firstChild.content.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
                       let identifier = element.attributes["id"] as String
                       println("  child id = \(identifier); content = \(content)")
                   }
               }
           }
       }
   }
   

   或者你可以这样做:

   let tutorialsParser = TFHpple(HTMLData: data)
   let tutorialsXPathString = "/html/body/ul/li"
   if let tutorialNodes = tutorialsParser.searchWithXPathQuery(tutorialsXPathString) as? [TFHppleElement] {
       for element in tutorialNodes {
           let content = element.firstChild.content.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
           let identifier = element.attributes["id"] as String
           println("id = \(identifier); content = \(content)")
   
           if let children = element.searchWithXPathQuery("/html/body/li/ul/li") as? [TFHppleElement] {
               for element in children {
                   let content = element.firstChild.content.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
                   let identifier = element.attributes["id"] as String
                   println("  child id = \(identifier); content = \(content)")
               }
           }
       }
   }