我有一本字典,其中包含从解析 JSON 中提取的其他字典中的子项。 结构如下所示:
{
children = (
{
children = (
{
hasArticles = 1;
hasWideIcon = 0;
label = biological;
urlId = 9950000123891;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = White;
urlId = 9950000123892;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "various flavors";
urlId = 9950000123893;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "different tastes creamy";
urlId = 9950000123894;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "yogurt drinks";
urlId = 9950000123895;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "Yogurt mix";
urlId = 9950000123896;
},
{
);
hasArticles = 0;
hasWideIcon = 0;
label = "types of yogurt"; //those above are the children of the "types of yogurt"
urlId = 9950000123890;
},
{
children = (
{
hasArticles = 1;
hasWideIcon = 0;
label = White;
urlId = 9950000123906;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "various flavors";
urlId = 9950000123907;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = Pappareale;
urlId = 9950000123909;
}
);
hasArticles = 0;
hasWideIcon = 0;
label = "yogurt healthy"; //those above are the children of the yogurt healthy
urlId = 9950000123905;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "puddings and creams";
urlId = 9950000123911;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "Snack dessert";
urlId = 9950000123913;
},
{
hasArticles = 1;
hasWideIcon = 0;
label = "various Dessert";
urlId = 9950000123914;
}
);
hasArticles = 0;
hasWideIcon = 0;
label = "Yogurt and Dessert ";
urlId = 9950000123889;
},
我的代码
-(void)connectionDidFinishLoading:(NSURLConnection *)connection{
NSLog(@"%d", [webData length]);
NSString *strResult =[[NSString alloc]initWithData:webData encoding:NSUTF8StringEncoding];
NSDictionary *result =[strResult JSONValue];
for (id obj in result){
NSLog(@"%@", result);
/*A part of the result is written above, but in reality is much
longer and includes all possible products in a supermarket*/
}
}
我如何提取“yogurtDessert”的 child
- 酸奶的种类(有 child 的)
- yogurt-healty(有 child )
- 布丁和奶油(没有 child )
- 点心甜品(不含 child )
- 各种甜点(不含 child )
我如何提取事先不知道的 yogurtDessert 的 child ?
我需要创建一个包含超市产品类别的字典数组(在这个例子中只有酸奶和甜点,总共 23 个元素),然后我必须创建另一个字典数组,每个字典包含子类别每件产品,即数千件。我考虑过使用 NSPredicate 但是是字典。 我必须在其他词典中过滤一个词典
最佳答案
字典的层次结构似乎包含两种类型的字典:代表类别的字典和代表产品的字典。
我在这里猜测叶子字典(没有 child )总是产品。具有子键的字典始终是类别。这可能不是真的——看起来 hasArticles
是 1 代表产品,0 代表类别——但同样,这是未知的。
这是提取所有产品的代码:
static void collectProducts(NSDictionary *dictionary, NSMutableArray *results)
{
NSArray *children == dictionary[@"children"];
if (children == nil) {
[results addObject:dictionary];
return;
}
for (NSDictionary *subDict in children)
collectProducts(subDict, results);
}
NSArray *findProducts(NSDictionary *dictionary)
{
NSMutableArray *result = [NSMutableArray array];
collectProducts(dictionary, result);
return array;
}
使用您的 JSON result
调用 findProducts
以获取所有叶字典。
关于ios - 过滤其他 NSDictionary 中的 NSDictionary,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15359162/