我正在为 iOS 开发与录音相关的移动应用程序。
由于这个事实,我正在开发一些不同的音效来修改录制的声音,但我在实现其中一些时遇到了问题。
我正在尝试创建回声/延迟效果,我需要将字节数组转换为短数组,但我不知道如何在 Objective-C 中执行此操作。
谢谢。
这是我当前实现它的源代码,但就像字节是一种非常短的类型,当我应用衰减(必须返回浮点值)时会在我的音频中产生可怕的噪音。
- (NSURL *)echo:(NSURL *)input output:(NSURL *)output{
int delay = 50000;
float attenuation = 0.5f;
NSMutableData *audioData = [NSMutableData dataWithContentsOfURL:input];
NSUInteger dataSize = [audioData length] - 44;
NSUInteger audioLength = [audioData length];
NSUInteger newAudioLength = audioLength + delay;
// Copy bytes
Byte *byteData = (Byte*)malloc(audioLength);
memcpy(byteData, [audioData bytes], audioLength);
short *shortData = (short*)malloc(audioLength/2);
// create a new array to store new modify data
Byte *newByteData = (Byte*)malloc(newAudioLength);
newByteData = byteData;
for (int i = 44; i < audioLength - delay; i++)
{
newByteData[i + delay] += byteData[i] * attenuation;
}
// Copy bytes in a new NSMutableData
NSMutableData *newAudioData = [NSMutableData dataWithBytes:newByteData length:newAudioLength];
// Store in a file
[newAudioData writeToFile:[output path] atomically:YES];
// Set WAV size
[[AudioUtils alloc] setAudioFileSize:output];
return output;
}
最佳答案
最后,我可以完成实现这四种方法的回声效果。我希望它们对您有用。
字节到短数组
- (short *) byte2short:(Byte *)bytes size:(int)size resultSize:(int)resultSize{
short *shorts = (short *)malloc(sizeof(short)*resultSize);
for (int i=0; i < size/2; i++){
shorts[i] = (bytes[i*2+1] << 8) | bytes[i*2];
}
return shorts;
}
短字节数组
- (Byte *) short2byte:(short *)shorts size:(int)size resultSize:(int)resultSize{
Byte *bytes = (Byte *)malloc(sizeof(Byte)*resultSize);
for (int i = 0; i < size; i++)
{
bytes[i * 2] = (Byte) (shorts[i] & 0x00FF);
bytes[(i * 2) + 1] = (Byte) (shorts[i] >> 8);
shorts[i] = 0;
}
return bytes;
}
效果
- (NSMutableData *) effect:(NSMutableData *)data delay:(int)delay attenuation:(float)attenuation{
NSUInteger audioLength = [data length];
// Copy original data in a byte array
Byte *byteData = (Byte*)malloc(sizeof(Byte)*audioLength);
memcpy(byteData, [data bytes], audioLength);
short *shortData = (short*)malloc(sizeof(short)*(audioLength/2 + delay));
shortData = [self byte2short:byteData size:(int)audioLength resultSize:(int)audioLength/2 + delay];
// Array to store shorts
short *newShortData = shortData;
for (int i = 44; i < audioLength/2; i++)
{
newShortData[i + delay] += (short)((float)shortData[i] * attenuation);
}
Byte *newByteData = [self short2byte:newShortData size:(int)(audioLength/2 + delay) resultSize:(int)(audioLength + delay*2)];
// Copy bytes to a NSMutableData in order to create new file
NSMutableData *newAudioData = [NSMutableData dataWithBytes:newByteData length:(int)(audioLength + delay*2)];
return newAudioData;
}
回声效果
- (NSURL *)echo:(NSURL *)input output:(NSURL *)output{
NSMutableData *audioData = [NSMutableData dataWithContentsOfURL:input];
// we call effect method that returns a NSMutableData and create a new file
[[self effect:audioData delay:6000 attenuation:0.5f] writeToFile:[output path] atomically:YES];
// We set file's size (is a method I have implemented)
[[AudioUtils alloc] setAudioFileSize:output];
return output;
}
关于ios - 如何使用 Objective-C 将字节数组转换为短数组?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21681545/