我有一个基于 Apache CXF 的网络服务和 Android 应用程序，它使用下面的代码向它发送请求。
现在我想编写一个简单的 iOS 应用程序，它向同一个 Web 服务发送相同的请求，但来自 iOS 设备。
什么是学习如何使用的良好起点
- JSON，
- 发送网络服务请求和
- 从服务器接收响应
在 Objective-C 中？
SaveLocationAsyncTask.java
public class SaveLocationAsyncTask extends
AbstractAsyncTask<SaveLocationRequest, SaveLocationResponse> implements
ISaveLocationAsyncTask {
private static final String SERVICE_NAME = "SaveLocation";
public SaveLocationAsyncTask(final IWebServiceTaskHelper aHelper,
final ILogger aLogger, final IServerUrlStorage aServerUrlStorage) {
super(aHelper, SaveLocationResponse.class, aLogger,
new CbResponseParser<SaveLocationResponse>(), aServerUrlStorage,
SERVICE_NAME);
}
}
AbstractAsyncTask.java
import android.os.AsyncTask;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.util.concurrent.ExecutionException;
public class AbstractAsyncTask<Request, Response> extends
AsyncTask<String, String, Response> implements
IRequestSender<Request, Response> {
private static final String REQUEST_AS_JSON_PARAMETER_NAME = "request";
private IWebServiceTaskHelper helper;
private Class<Response> responseClass;
private ILogger logger = null;
private IResponseParser<Response> responseParser = null;
private IServerUrlStorage serverUrlStorage;
private String serviceName;
public AbstractAsyncTask(final IWebServiceTaskHelper aHelper,
final Class<Response> aResponseClass, final ILogger aLogger,
final IResponseParser<Response> aResponseParser,
final IServerUrlStorage aServerUrlStorage, final String aServiceName) {
helper = aHelper;
responseClass = aResponseClass;
logger = aLogger;
responseParser = aResponseParser;
serverUrlStorage = aServerUrlStorage;
serviceName = aServiceName;
}
private String convertToJson(final Object aRequest) {
final ObjectMapper mapper = new ObjectMapper();
String json = null;
try {
json = mapper.writeValueAsString(aRequest);
} catch (final JsonProcessingException exception) {
logger.error(exception);
}
return json;
}
@Override
protected Response doInBackground(final String... aParams) {
logger.debug("doInBackground: " + aParams);
return new ResponseProcessor<Response>(logger, helper, responseParser,
responseClass).processResponse(aParams);
}
@Override
public Response sendRequest(final Request aRequest)
throws InterruptedException, ExecutionException {
final String json = convertToJson(aRequest);
final String url = serverUrlStorage.getServerUrl() + serviceName;
helper.addNameValuePair(REQUEST_AS_JSON_PARAMETER_NAME, json);
execute(url);
return get();
}
}
CbResponseParser.java:
import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
public class CbResponseParser<Response> implements IResponseParser<Response> {
@Override
public Response parseResponse(final String aResponseAsString,
final Class<Response> aClass) throws IOException, JsonParseException,
JsonMappingException {
final ObjectMapper mapper = new ObjectMapper();
final Response response = mapper.readValue(aResponseAsString, aClass);
return response;
}
}
更新 1(14.06.2014 15:47 MSD):
我试过 DJ_Lectr0 的方法。存在一个问题:服务器找不到网络服务。这是日志输出:
WARNING: No operation matching request path "/mobilecsdemo-server/mobilecsdemo/TestMessage" is found, Relative Path: /, HTTP Method: POST, ContentType: application/json, Accept: application/json,. Please enable FINE/TRACE log level for more details.
beans.xml 片段:
<bean id="TestMessage" class="ru.mycompany.mobilecsdemo.server.services.TestMessage"/>
<jaxrs:server id="services" address="/">
<jaxrs:serviceBeans>
<ref bean="TestMessage"/>
</jaxrs:serviceBeans>
</jaxrs:server>
测试消息 bean :
@Path("/TestMessage")
public class TestMessage {
private static final Logger LOGGER = LoggerFactory.getLogger(TestMessage.class);
@POST
@Produces("text/plain")
public String processTestMessage(@FormParam("request") final String aRequest)
{
try {
final ObjectMapper mapper = new ObjectMapper();
final TestMessageRequest request = mapper.readValue(aRequest,
TestMessageRequest.class);
final TestMessageResponse response = new TestMessageResponse();
response.setResponse(request.getMessage() + " - Response");
return mapper.writeValueAsString(response);
} catch (final JsonParseException exception) {
LOGGER.error("getUserId", exception);
} catch (final JsonMappingException exception) {
LOGGER.error("getUserId", exception);
} catch (final IOException exception) {
LOGGER.error("getUserId", exception);
}
return "";
}
}
Web 服务 TestMessage 的 URL 似乎是 http://AAA.BBB.CCC.DDD:8080/mobilecsdemo-server/mobilecsdemo/TestMessage。
iOS端发送请求代码:
NSDictionary *data = [NSDictionary dictionaryWithObject:@"test sending ios" forKey:@"message"];
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:data options:kNilOptions error:&error];
NSURL *url = [NSURL URLWithString:@"http://AAA.BBB.CCC.DDD:8080/mobilecsdemo-server/mobilecsdemo/TestMessage"];
NSMutableURLRequest *req = [NSMutableURLRequest requestWithURL:url cachePolicy:nil timeoutInterval:60];
[req setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[req setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[req setValue:[NSString stringWithFormat:@"%d", [jsonData length]] forHTTPHeaderField:@"Content-Length"];
[req setHTTPMethod:@"POST"];
[req setHTTPBody:jsonData];
NSString *retStr = [[NSString alloc] initWithData:[NSURLConnection sendSynchronousRequest:req returningResponse:nil error:nil] encoding:NSUTF8StringEncoding];
NSLog(@"Response: %@", retStr);
http://AAA.BBB.CCC.DDD:8080/mobilecsdemo-server/mobilecsdemo?_wadl 显示如下:
<application xmlns="http://wadl.dev.java.net/2009/02" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<grammars/>
<resources base="http://AAA.BBB.CCC.DDD:8080/mobilecsdemo-server/mobilecsdemo/">
<resource path="/TestMessage">
<method name="POST">
<request>
<representation mediaType="application/x-www-form-urlencoded">
<param name="request" style="query" type="xs:string"/>
</representation>
</request>
<response>
<representation mediaType="text/plain">
<param name="result" style="plain" type="xs:string"/>
</representation>
</response>
</method>
</resource>
</resources>
</application>
我试图在 iOS 端将 Accept 和 Content-Type 更改为 application/x-www-form-urlencoded，但是它没有帮助。
更新 2 (16:36 MSD): 尝试使用 Fiddler2 发送请求并且这个有效:
更新 3 (17:12 MSD):这个似乎有效。
NSDictionary *data = [NSDictionary dictionaryWithObject:@"test sending ios" forKey:@"message"];
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:data options:kNilOptions error:&error];
NSURL *url = [NSURL URLWithString:@"http://AAA.BBB.CCC.DDD:8080/mobilecsdemo-server/mobilecsdemo/TestMessage"];
NSMutableURLRequest *req = [NSMutableURLRequest requestWithURL:url cachePolicy:nil timeoutInterval:60];
[req setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[req setValue:[NSString stringWithFormat:@"%d", [jsonData length]] forHTTPHeaderField:@"Content-Length"];
[req setHTTPMethod:@"POST"];
NSString* body = @"request={\"message\":\"message content\"}";
NSData *someData = [body dataUsingEncoding:NSUTF8StringEncoding];
[req setHTTPBody:someData];
NSString *retStr = [[NSString alloc] initWithData:[NSURLConnection sendSynchronousRequest:req returningResponse:nil error:nil] encoding:NSUTF8StringEncoding];
NSLog(@"jsonData: %@", jsonData);
NSLog(@"Response: %@", retStr);
最佳答案
这将为您服务。根据您的需要调整 NSDictionary。
NSDictionary *data = [NSDictionary dictionaryWithObject:@"test sending ios" forKey:@"value1"];
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:data options:kNilOptions error:&error];
NSURL *url = [NSURL URLWithString:@"http://webserveraddress"];
NSMutableURLRequest *req = [NSMutableURLRequest requestWithURL:url cachePolicy:nil timeoutInterval:60];
[req setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[req setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[req setValue:[NSString stringWithFormat:@"%d", [jsonData length]] forHTTPHeaderField:@"Content-Length"];
[req setHTTPMethod:@"POST"];
[req setHTTPBody:jsonData];
NSString *retStr = [[NSString alloc] initWithData:[NSURLConnection sendSynchronousRequest:req returningResponse:nil error:nil] encoding:NSUTF8StringEncoding];
NSURLConnection还有一个异步方法:
[NSURLConnection sendAsynchronousRequest:req queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *res3, NSData *data, NSError *connectionError) {
NSString *retStr = [[NSString alloc] initWithData:data];
}
正如 Rohan Panchal 在评论中提到的那样 AFNetworking是一个非常棒的第 3 方库，很好地包装了这些方法。我个人更喜欢简单的 NSURLConnection 方法。
关于ios - 如何在 iOS 中发送和接收 Web 服务请求和响应？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/24210726/