ios - Swift2 的数组

Question

我有两个单独的 .swift 文件。我想使用 ManagePerson.swift 来管理我的 Strings，例如添加和检索。另一个 ViewController.swift 创建一个 ManagePerson 类数组来访问数据。

在我的 ManagePerson.swift 中

func addPerson(name: String, code: String, description: String){
    self.name = name
    self.code = code
    self.description = description
}

在我的 ViewController.swift 中。

var personList = [PersonTable]() // Declared at class level

for jsonObjectString in resultArray! {
    let name = jsonObjectString["Name"] as! String
    let code = jsonObjectString["Code"] as! String
    let description = jsonObjectString["Description"] as! String
    self.personList[count].addPerson(Name, code: code, description: description)
    count++
}

但是，我似乎无法执行.addPerson 方法。我收到错误消息“Thread: 6: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subcode=0x0)”

Answer 1

首先，假设您使用 (a) 三个属性定义了“person”类；和 (b) init 方法来设置这些属性:

class Person {
    let name: String
    let code: String
    let description: String

    init(name: String, code: String, description: String) {
        self.name = name
        self.code = code
        self.description = description
    }
}

然后，要实例化一个Person，就是

let person = Person(name: "Joe Montana", code: "16", description: "Quarterback")

如果您想要这些 Person 对象的数组，您可以将其定义为:

var personList = [Person]()

因此，要将 Person 添加到此数组，它是:

personList.append(Person(name: "Joe Montana", code: "16", description: "Quarterback"))

因此，如果 resultArray 是字典数组，您可以像这样添加项目:

for dictionary in resultArray! {
    let name = dictionary["Name"] as! String
    let code = dictionary["Code"] as! String
    let description = dictionary["Description"] as! String
    personList.append(Person(name: name, code: code, description: description))
}

但是，请注意，我们不必弄乱 count(因为您可以直接添加到数组中)。

或者，如果这些值可以是 nil，您可以将它们定义为可选值:

class Person {
    let name: String?
    let code: String?
    let description: String?

    init(name: String?, code: String?, description: String?) {
        self.name = name
        self.code = code
        self.description = description
    }
}

和

for dictionary in resultArray! {
    let name = dictionary["Name"] as? String
    let code = dictionary["Code"] as? String
    let description = dictionary["Description"] as? String
    personList.append(Person(name: name, code: code, description: description))
}