我有这个功能:
- (void)checkLogin:(NSString *)pLogin andPassword:(NSString*) pPassword {
//Create the data object.
NSMutableDictionary *tLoginAndPasword = [NSMutableDictionary dictionaryWithObjectsAndKeys:pLogin,@"Login",pPassword,@"Password", nil];
NSMutableDictionary *tData = [NSMutableDictionary dictionaryWithObjectsAndKeys:[_Util serializeDictionary:tLoginAndPasword],@"Data", nil];
//Call the login method.
NSData *tResponse = [_Util getLogin:tData];
if (tResponse != Nil) {
_oLabelErrorLogin.hidden = YES;
[_Util setUser:pLogin andPassword:pPassword];
NSMutableDictionary *tJSONResponse =[NSJSONSerialization JSONObjectWithData:tResponse options:kNilOptions error:nil];
NSString *tPayload = [tJSONResponse objectForKey:@"Payload"];
if([[tJSONResponse objectForKey:@"StatusCode"] isEqual: @"424"]) {
//Set global values.
NSData *tPayloadData = [tPayload dataUsingEncoding:NSUTF8StringEncoding];
if ([NSJSONSerialization isValidJSONObject:tPayloadData]) {
_Payload = [NSJSONSerialization JSONObjectWithData:tPayloadData options:kNilOptions error:nil];
_RowCount = _Payload.count;
} else {
NSLog(@"JSON Wrong String %@",tPayload);
}
} else if([[tJSONResponse objectForKey:@"StatusCode"] isEqual: @"200"]){
_Payload = Nil;
}
} else {
//Set global values.
_Payload = Nil;
_oLabelErrorLogin.hidden = NO;
//Clear login data.
_oLogin.text = @"";
_oPassword.text = @"";
[_Util setUser:@"" andPassword:@""];
}
}
JSON 响应如下所示:
{
"Payload": "{\"UserName\":\"Marco Uzcátegui\",\"Clients\":[{\"UserProfileId\":4,\"ProfileName\":\"Platform Administrator\",\"ClientName\":\"Smart Hotel Platform\",\"InSession\":true},{\"UserProfileId\":5,\"ProfileName\":\"Administrator\",\"ClientName\":\"La Moncloa de San Lázaro\",\"InSession\":false},{\"UserProfileId\":6,\"ProfileName\":\"Administrator\",\"ClientName\":\"Jardín Tecina\",\"InSession\":false}]}",
"StatusCode": "424",
"StatusDescription": null
}
如您所见,我在“Payload”中有一个转义字符串,它是一个正确的 JSON,所以我想用该字符串生成另一个 NSMutableDictionary,所以我这样做:
NSData *tPayloadData = [tPayload dataUsingEncoding:NSUTF8StringEncoding];
if ([NSJSONSerialization isValidJSONObject:tPayloadData]) {
_Payload = [NSJSONSerialization JSONObjectWithData:tPayloadData options:kNilOptions error:nil];
_RowCount = _Payload.count;
} else {
NSLog(@"JSON Wrong String %@",tPayload);
}
所以我从 NSString 创建一个 NSData 并询问它是否有效,它总是返回 false。
我已尝试替换字符串中的“\”,但没有成功。
[tPayload stringByReplacingOccurrencesOfString:@"\\\"" withString:@""]
我试图用字符串创建一个 NSMutableDictionary,但结果不是字典。
NSMutableDictionary *tPayload = [tJSONResponse objectForKey:@"Payload"];
我有点迷路了。
我们将不胜感激。
问候。
最佳答案
问题是这一行
[NSJSONSerialization isValidJSONObject:tPayloadData]
来自isValidJSONObject
的文档
Returns a Boolean value that indicates whether a given object can be converted to JSON data.
given object 表示 NSArray
或 NSDictionary
但不是 NSData
删除检查并实现 JSONObjectWithDataoptions:error:
中的错误参数
关于ios - 使用 NSJSONSerialization 将 NSString 转换为 JSON 不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34897559/