我正在尝试将一个相当长的字符串的内容拆分为内容页面。现在我按字符(每页 500 个字符)这样做:
//Lets find out how many pages to make
int pageLength = 500; //how many characters per page
NSString *text = ((Story *) [self.story objectAtIndex:chapter]).content;
int NumberOfPages = (text.length/pageLength);
//NumberOfPages += 1;
//Build the Pages Array
NSMutableArray *pageStrings = [[NSMutableArray alloc] init];
for (int i = 0; i <= (NumberOfPages+1); i++)
{
if (i < NumberOfPages) {
//Load the text like normal
NSString *contentString = [[NSString alloc]initWithFormat:@"<html><head><style type=text/css>body {font-family: \"%@\"; font-size: %d;}</style></head><body><p>%@</p></body></htlm>",@"helvetica",20,[text substringWithRange:NSMakeRange(i*pageLength,pageLength)]];
[pageStrings addObject:contentString];
}
if (i == NumberOfPages) {
//on the last page, only load what's available
NSString *contentString = [[NSString alloc]initWithFormat:@"<html><head><style type=text/css>body {font-family: \"%@\"; font-size: %d;}</style></head><body><p>%@</p></body></htlm>",@"helvetica",20,[text substringWithRange:NSMakeRange(i*pageLength,(text.length-(i*pageLength)))]];
[pageStrings addObject:contentString];
}
if (i > NumberOfPages){
//add in a blank page on the end
NSString *contentString = [[NSString alloc]initWithFormat:@"<html><head><style type=text/css>body {font-family: \"%@\"; font-size: %d;}</style></head><body><p>%@</p></body></htlm>",@"helvetica",20,@"What do you do?"];
[pageStrings addObject:contentString];
}
}
pageContent = [[NSArray alloc] initWithArray:pageStrings];
这很好用，但通常会以单词在中间分开而告终。我试图让它在这个词上 split 。该字符串不必正好是 500 个字符，只需接近它即可。
最佳答案
如果你想“正确”地做到这一点，你应该看看 NSString 方法:
- (void)enumerateSubstringsInRange:(NSRange)range options:(NSStringEnumerationOptions)opts usingBlock:(void (^)(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop))block
您可以按单词、行、段落、句子和字符序列智能地枚举文本。
Session 128，WWDC 2011，“高级文本处理”对此有一些很好的信息。
关于ios - 将字符串拆分为 Objective-C 中的内容页面，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12046816/