ios - 使用对象对 NSArray 进行排序

Question

我有一个包含以下数据的 NSDictionary:

(lldb) po allFriends
{
    71685207018702188 =     {
        id = 71685207018702188;
        name = "mikeziri ";
        username = mi;
    };
    93374822540641772 =     {
        id = 93374822540641772;
        name = "Alan Weclipse";
        username = zuka;
    };
    96553685978449395 =     {
        id = 96553685978449395;
        name = "Monica Weclipse";
        username = amonica;
    };
    96556113096345076 =     {
        id = 96556113096345076;
        name = Xavier;
        username = branko;
    };
    97017008427632119 =     {
        id = 97017008427632119;
        name = "Dario Weclipse";
        username = tarzan;
    };
}

我根据名称对这些对象进行排序，如果它们没有名称，我将使用用户名。为此，我使用 name 和 id 创建了一个新的 NSDictionary，并在方法结束时按 name 对它们进行排序。对它们进行排序的代码如下:

- (NSArray*)orderFriends
{
    NSMutableDictionary* newFriendsDict = [[NSMutableDictionary alloc] init];

    for (int i=0; i<[allFriends count];i++)
    {
        NSMutableDictionary* friendsDict = [[NSMutableDictionary alloc] init];
        NSDictionary* friend = [allFriends objectForKey:[NSString stringWithFormat:@"%@", [sortedKeysFriends objectAtIndex:i]]];

        if ([[friend objectForKey:@"name"] length] != 0)
        {
            [friendsDict setObject:[friend objectForKey:@"id"] forKey:@"id"];
            [friendsDict setObject:[NSString stringWithFormat:@"%@", [friend objectForKey:@"name"]] forKey:@"name"];
        }
        else
        {
            [friendsDict setObject:[friend objectForKey:@"id"] forKey:@"id"];
            [friendsDict setObject:[NSString stringWithFormat:@"%@", [friend objectForKey:@"username"]] forKey:@"name"];
        }

        [newFriendsDict setObject:friendsDict forKey:[NSNumber numberWithInt:i]];
    }

    NSArray* sp = nil;
    sp = [[newFriendsDict allValues] sortedArrayUsingComparator:^(id obj1, id obj2){
        NSString *one = [NSString stringWithFormat:@"%@", [obj1 objectForKey:@"name"]];
        NSString *two = [NSString stringWithFormat:@"%@", [obj2 objectForKey:@"name"]];

        return [one compare:two];
    }];

    return sp;
}

问题是最终结果是错误的:

(lldb) po sp
<__NSArrayI 0x160491a0>(
{
    id = 93374822540641772;
    name = "Alan Weclipse";
},
{
    id = 97017008427632119;
    name = "Dario Weclipse";
},
{
    id = 96553685978449395;
    name = "Monica Weclipse";
},
{
    id = 96556113096345076;
    name = Xavier;
},
{
    id = 71685207018702188;
    name = "mikeziri ";
},
)

Answer 1

区分大小写。使所有字符串变小或变大。