ios - NSPredicate 获取包含特定键值的数组

Question

使用item-"apple"获取数组的所有元素

我的意见

item_list: [
    {
        CurrentDate = “4/2/2016";
        search_item =(             
            item_name = @“apple”;
        );
    },
    {
        CurrentDate = “27/1/2016";
        search_item =(
            item_name = @“Ball”;   
        );
    },
    {
        CurrentDate = “17/2/2016";
        search_item =(
            item_name = @“Cat”; 
        );
    },
    {
        CurrentDate = “6/2/2016";
        search_item =(
            item_name = @“apple”;
        );
    },
]

我需要的输出

item_list: [
    {
        CurrentDate = “4/2/2016";
        search_item =(             
            item_name = @“apple”;
        );
    },
    {
        CurrentDate = “6/2/2016";
        search_item =(
            item_name = @“apple”;
        );
    },
]

我尝试但无法运行的代码

NSArray*  filtered = [[item_list valueForKey:@"search_item"] filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(item_name == %@)", @“apple”]];

Answer 1

NSPredicate *predicate =
[NSPredicate predicateWithFormat:@"ANY search_item.item_name CONTAINS[c] %@", @"apple"];  
NSArray *array =[item_list filteredArrayUsingPredicate:predicate];