我在 Xcode 7.1 中使用以下代码创建了一个 Swift Playground,它的评估速度非常慢(通常需要几分钟)。为什么会发生这种情况?由于它使 Playground 基本上无法使用,我可以采取什么措施来缩短其执行时间吗?
let sets = [
"TEMPERATURE":[
(value:37.0, attributes:["A":0.0, "B":0.2]),
(value:37.5, attributes:["A":0.0, "B":1.0]),
(value:38.0, attributes:["A":0.2, "B":0.5]),
(value:38.5, attributes:["A":0.5, "B":0.2]),
(value:39.0, attributes:["A":0.8, "B":0.0]),
(value:39.5, attributes:["A":1.0, "B":0.0]),
(value:40.0, attributes:["A":1.0, "B":0.0]),
],
"VARIATION":[
(value:0.0, attributes:["A":0.0, "B":1.0]),
(value:2.0, attributes:["A":0.2, "B":0.8]),
(value:5.0, attributes:["A":0.5, "B":0.5]),
(value:8.0, attributes:["A":0.8, "B":0.2]),
(value:10.0, attributes:["A":1.0, "B":0.0]),
]
]
最佳答案
这里的问题是 Swift 编译器在推导集合
的类型时非常慢。如果您将类型明确化,Swift 编译器将不必花费任何时间来推导它。试试这个:
let sets: [String:[(value: Double, attributes:[String:Double])]] = [
"TEMPERATURE":[
(value:37.0, attributes:["A":0.0, "B":0.2]),
(value:37.5, attributes:["A":0.0, "B":1.0]),
(value:38.0, attributes:["A":0.2, "B":0.5]),
(value:38.5, attributes:["A":0.5, "B":0.2]),
(value:39.0, attributes:["A":0.8, "B":0.0]),
(value:39.5, attributes:["A":1.0, "B":0.0]),
(value:40.0, attributes:["A":1.0, "B":0.0]),
],
"VARIATION":[
(value:0.0, attributes:["A":0.0, "B":1.0]),
(value:2.0, attributes:["A":0.2, "B":0.8]),
(value:5.0, attributes:["A":0.5, "B":0.5]),
(value:8.0, attributes:["A":0.8, "B":0.2]),
(value:10.0, attributes:["A":1.0, "B":0.0]),
]
]
关于带有字典的 Swift Playground 太慢,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33310855/