我创建了一个从普通字符串生成属性字符串的方法。 attrString
以下值非空且内容正确。
运行我的应用程序后,第二行失败并显示 EXC_BAD_ACCESS
.知道为什么吗?
__bridge_retained
call 是 iOS 5 的要求 afaik。我也试过 __bridge
但这没有效果,问题仍然存在。
NSMutableAttributedString *attrString = (NSMutableAttributedString*)[textLayer attributedString];
CTFramesetterRef framesetter = CTFramesetterCreateWithAttributedString((__bridge_retained CFMutableAttributedStringRef)attrString);
更新
如果我这样做:
NSMutableAttributedString *attrString = (NSMutableAttributedString*)[textLayer attributedString];
NSLog(@"%@", attrString);
CTFramesetterRef framesetter = CTFramesetterCreateWithAttributedString((__bridge CFMutableAttributedStringRef)attrString);
然后 NSLog
行不会编译; Xcode 发出警告 和 错误说明 "Incompatible pointer types passing 'char[3]' to parameter of type 'NSString *'"
.
所以我尝试了这个:
NSLog([attrString description]);
这会产生以下输出(出于隐私考虑,我已将字符串内容替换为 <snipped>
):
2012-01-19 06:49:11.307 WritePath[2475:707] <Snipped>
{
CTForegroundColor = "<CGColor 0x281530> [<CGColorSpace 0x22d1a0> (kCGColorSpaceDeviceRGB)] ( 0 0 0 1 )";
NSFont = "<CGFont (0x28f850): ArialMT>";
NSParagraphStyle = "CTParagraphStyle:\nwriting direction = -1, alignment = 3, line break mode = 0, default tab interval = 0\nfirst line head indent = 0, head indent = 0, tail indent = 0\nline height multiple = 0, maximum line height = 0, minimum line height = 0\nline spacing adjustment = 0, paragraph spacing = 0, paragraph spacing before = 0\ntabs:\n<CFArray 0x287b50 [0x3f229630]>{type = immutable, count = 12, values = (\n\t0 : CTTextTab: location = 28, alignment = 0, options = (none)\n\n\t1 : CTTextTab: location = 56, alignment = 0, options = (none)\n\n\t2 : CTTextTab: location = 84, alignment = 0, options = (none)\n\n\t3 : CTTextTab: location = 112, alignment = 0, options = (none)\n\n\t4 : CTTextTab: location = 140, alignment = 0, options = (none)\n\n\t5 : CTTextTab: location = 168, alignment = 0, options = (none)\n\n\t6 : CTTextTab: location = 196, alignment = 0, options = (none)\n\n\t7 : CTTextTab: location = 224, alignment = 0, options = (none)\n\n\t8 : CTTextTab: location = 252, alignment = 0, options = (none)\n\n\t9 : CTTextTab: location = 280, alignment = 0, options = (none)\n\n\t10 : CTTextTab: location = 308, alignment = 0, options = (none)\n\n\t11 : CTTextTab: location = 336, alignment = 0, options = (none)\n\n)}";
}
最佳答案
我在您的属性字符串转储中注意到了这一点:
NSFont = "<CGFont (0x28f850): ArialMT>"
您是否使用 CGFontRef
作为 kCTFontAttributeName
键的值创建了属性字符串?您必须使用 CTFontRef
,而不是 CGFontRef
。它们是不同的。
关于iOS:CTFramesetterCreateWithAttributedString 导致 EXC_BAD_ACCESS,任何猜测原因?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8918174/