ios - 使用 Swift 和 Storyboard 在两个 UIViewController 之间传递数据

Question

我使用下面的代码来选择 UITableView 在 UIViewController 之间传递数据

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
    if ([segue.identifier isEqualToString:@"showRecipeDetail"]) {
        NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];
        RecipeDetailViewController *destViewController = segue.destinationViewController;
        destViewController.recipeName = [recipes objectAtIndex:indexPath.row];
    }
}

如何使用 swift 对 tableView 选定的数据执行相同的操作？

我尝试了以下简单传递的方法，该方法有效
但是如何复制上述案例。

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {

    var detailsVC = segue.destinationViewController as SecondViewController

    detailsVC.passedString = "hello"

}

Answer 1

这应该有效:

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    if segue.identifier == "showRecipeDetail" {

            var detailsVC = segue.destinationViewController as SecondViewController
            let indexPath = tableView.indexPathForSelectedRow()
            detailsVC.passedString = recipes![indexPath?row]
            //or try that if above doesn't work: detailsVC.passedString = recipes[indexPath?row]
        }
    }
}

此行可能需要修改:

destViewController?.destViewController.recipeName = recipes![i]

这取决于您的属性是否可选(也许您必须删除？或!)