我使用了这个 https://codepen.io/alisuarez/pen/RWGNLm 中使用的 jQuery
这里的问题是因为在函数中使用了类,所以所有星级评级同时起作用。在 jQuery 中,当我使用 ID 时,它按预期适用于一行特定的评级。我正在将该行动态地克隆为多行。如何为每个 id star-rating1、star-rating2 等运行 jQuery? 任何帮助将不胜感激。提前致谢!
var $star_rating = $('#star-rating .fa');
var SetRatingStar = function() {
return $star_rating.each(function() {
if (parseInt($star_rating.siblings('input.rating-value').val()) >=
parseInt($(this).data('rating'))) {
return $(this).removeClass('fa-star-o').addClass('fa-star');
} else {
return $(this).removeClass('fa-star').addClass('fa-star-o');
}
});
};
$star_rating.on('click', function() {
$star_rating.siblings('input.rating-value').val($(this).data('rating'));
return SetRatingStar();
});
SetRatingStar();
<link href="//maxcdn.bootstrapcdn.com/font-awesome/4.4.0/css/font-awesome.min.css" rel="stylesheet" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div class="row">
<div class="col-lg-12">
<div class="star-rating" id="star-rating">
<span class="fa fa-star-o" data-rating="1"></span>
<span class="fa fa-star-o" data-rating="2"></span>
<span class="fa fa-star-o" data-rating="3"></span>
<span class="fa fa-star-o" data-rating="4"></span>
<span class="fa fa-star-o" data-rating="5"></span>
<input type="hidden" name="whatever1" class="rating-value" value="2.56">
</div>
</div>
</div>
<div class="row">
<div class="col-lg-12">
<div class="star-rating" id="star-rating">
<span class="fa fa-star-o" data-rating="1"></span>
<span class="fa fa-star-o" data-rating="2"></span>
<span class="fa fa-star-o" data-rating="3"></span>
<span class="fa fa-star-o" data-rating="4"></span>
<span class="fa fa-star-o" data-rating="5"></span>
<input type="hidden" name="whatever2" class="rating-value" value="1.9">
</div>
</div>
</div>
最佳答案
以下代码按预期工作
HTML
<div class="container">
<div class="row">
<div class="col-lg-12 abc">
<div class="star-rating">
<span class="fa fa-star-o" data-rating="1"></span>
<span class="fa fa-star-o" data-rating="2"></span>
<span class="fa fa-star-o" data-rating="3"></span>
<span class="fa fa-star-o" data-rating="4"></span>
<span class="fa fa-star-o" data-rating="5"></span>
<input type="hidden" name="whatever1" class="rating-value" value="2.56">
</div>
</div>
</div>
<div class="row">
<div class="col-lg-12 abc">
<div class="star-rating">
<span class="fa fa-star-o" data-rating="1"></span>
<span class="fa fa-star-o" data-rating="2"></span>
<span class="fa fa-star-o" data-rating="3"></span>
<span class="fa fa-star-o" data-rating="4"></span>
<span class="fa fa-star-o" data-rating="5"></span>
<input type="hidden" name="whatever2" class="rating-value" value="1.9">
</div>
</div>
</div>
</div>
JQUERY
$('.abc').click(function(){
var $star_rating = $(this).find('.star-rating .fa');
var SetRatingStar = function() {
return $star_rating.each(function() {
if (parseInt($star_rating.siblings('input.rating-value').val()) >= parseInt($(this).data('rating'))) {
return $(this).removeClass('fa-star-o').addClass('fa-star');
} else {
return $(this).removeClass('fa-star').addClass('fa-star-o');
}
});
};
$star_rating.on('click', function() {
$star_rating.siblings('input.rating-value').val($(this).data('rating'));
return SetRatingStar();
});
});
SetRatingStar();
关于jquery - 星级评分 jquery 不适用于多个实例,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46056486/