如何使用css查找同级的一些元素?
<p class=h1>a</p>
<p class=h2>a1</p>
<p class=h3>a11</p>
<p class=h3>a12</p>
<p class=h2>a2</p>
<p class='h1 current'>b</p>
<p class=h2>b1</p>
<p class=h3>b11</p>
<p class=h3>b12</p>
<p class=h2>b2</p>
<p class=h1>c</p>
<p class=h2>c1</p>
<p class=h2>c2</p>
我想用css获取下面的元素,应该怎么找?
我试图像这样找到它 .current~p:not(.current~.h1~p)
,但失败了。
<p class=h2>b1</p>
<p class=h3>b11</p>
<p class=h3>b12</p>
<p class=h2>b2</p>
最佳答案
根据我对你的问题的理解,你想解决 .h1.current< 之后的所有
段落,但您希望任何遵循非 .h2
和 .h3
段落.current
的间歇性 .h1
的人不被规则处理。
唉,这在当前的 CSS 层中是不可能的,因为 :not()
伪类只能采用简单的 CSS 选择器,而不能采用复杂的选择器。
但是你可以尝试解决以下 sibling 并将样式恢复为初始值,就像这样。
.h1 {
margin-left: 10px;
text-decoration: underline double orange;
}
.h2 {
margin-left: 30px;
/* *1* */
text-decoration: underline solid green;
}
.h3 {
margin-left: 50px;
/* *2* */
text-decoration: underline overline dashed blue;
}
/* This gets all the followers to .h1.current which are .h2 or .h3 */
.h1.current~.h2,
.h1.current~.h3 {
/* *3* */
text-decoration: line-through double red;
}
/* this gets all .h2 followers of .h1 which itself follows .h1.current */
.h1.current~.h1~.h2 {
/* overwrite *3* by copying *1* properties */
text-decoration: underline solid green;
}
/* this gets all .h3 followers of .h1 which itself follows .h1.current */
.h1.current~.h1~.h3 {
/* overwrite *3* by copying *2* properties */
text-decoration: underline overline dashed blue;
}
<p class=h1>a (not this)</p>
<p class=h2>a1 (not this)</p>
<p class=h3>a11 (not this)</p>
<p class=h3>a12 (not this)</p>
<p class=h2>a2 (not this)</p>
<p class='h1 current'>b (this is current)</p>
<p class=h2>b1 (this)</p>
<p class=h3>b11 (this)</p>
<p class=h3>b12 (this)</p>
<p class=h2>b2 (this)</p>
<p class=h1>c (breaks the above chain)</p>
<p class=h2>c1 (not this)</p>
<p class=h3>c21 (not this)</p>
<p class=h3>c22 (not this)</p>
<p class=h2>c2 (not this)</p>
此规则应适用于 CSS4
.h1.current ~ p:is(.h2, .h3):not(.h1.current ~ .h1:not(.current) ~ p)
但我们现在不能使用它。然而,jQuery 确实支持 :not
伪类中的复杂选择器(但不支持 :is()
),因此这里是支持 jQuery 的相同示例
.h1.current ~ p:not(.h1):not(.h1.current ~ .h1:not(.current) ~ p)
jQuery('.h1.current ~ p.h2:not(.h1.current ~ .h1:not(.current) ~ p), .h1.current ~ p.h3:not(.h1.current ~ .h1:not(.current) ~ p)').css('backgroundColor', 'magenta')
.h1 {
margin-left: 10px;
text-decoration: underline double orange;
}
.h2 {
margin-left: 30px;
/* *1* */
text-decoration: underline solid green;
}
.h3 {
margin-left: 50px;
/* *2* */
text-decoration: underline overline dashed blue;
}
/* This gets all the followers to .h1.current which are .h2 or .h3 */
.h1.current~.h2,
.h1.current~.h3 {
/* *3* */
text-decoration: line-through double red;
}
/* this gets all .h2 followers of .h1 which itself follows .h1.current */
.h1.current~.h1~.h2 {
/* overwrite *3* by copying *1* properties */
text-decoration: underline solid green;
}
/* this gets all .h3 followers of .h1 which itself follows .h1.current */
.h1.current~.h1~.h3 {
/* overwrite *3* by copying *2* properties */
text-decoration: underline overline dashed blue;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<p class=h1>a (not this)</p>
<p class=h2>a1 (not this)</p>
<p class=h3>a11 (not this)</p>
<p class=h3>a12 (not this)</p>
<p class=h2>a2 (not this)</p>
<p class='h1 current'>b (this is current)</p>
<p class=h2>b1 (this)</p>
<p class=h3>b11 (this)</p>
<p class=h3>b12 (this)</p>
<p class=h2>b2 (this)</p>
<p class=h1>c (breaks the above chain)</p>
<p class=h2>c1 (not this)</p>
<p class=h3>c21 (not this)</p>
<p class=h3>c22 (not this)</p>
<p class=h2>c2 (not this)</p>
关于html - 如何用css找到一些同级的元素?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55917459/