我创建了一个 jquery 动画,当您单击其中一个按钮时,隐藏的 div 从 left: -650px;
滑动到 left: 0px;
click here to see example但是我注意到,当您单击另一个按钮以显示另一个隐藏的 div 时,之前隐藏的 div 不会返回到它的原始位置 left: -650px;
它停留在 left: 0;有谁知道我需要添加什么才能实现这一目标......?
HTML:
<div id="wrapper">
<div class="top-block">
<ul>
<li><a id="one" href="#" class="proBtn">block</a>
</li>
<li><a id="two" href="#" class="proBtn">test</a>
</li>
<li><a id="three" href="#" class="proBtn">test</a>
</li>
<li><a id="four" href="#" class="proBtn">Lists</a>
</li>
<li><a href="#" class="proBtn">hello</a>
</li>
<li><a href="#" class="proBtn">test</a>
</li>
</ul>
<!-- HOME SECTION -->
<div id="one-bck" class="mid-block fadeInLeft" style="background:green;"></div>
<div id="two-bck" class="mid-block fadeInLeft" style="background:red;"></div>
<div id="three-bck" class="mid-block fadeInLeft"></div>
<div id="four-bck" class="mid-block fadeInLeft"></div>
</div>
</div>
JS
$(document).ready(function () {
$('.proBtn').click(function () {
$('li').removeClass('active');
$('li a').removeClass('blue');
$(this).parent("li").addClass('active');
$(this).addClass('blue');
});
$('#one').click(function () {
$('#two-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#three-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#four-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#one-bck').addClass('animated').animate({
left: '0px',
opacity: 1
}, 500);
});
$('#two').click(function () {
$('#one-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#three-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#four-bck').animate({
left: '-650px;',
opacity: 0
}, 1500).removeClass('animated');
$('#two-bck').addClass('animated').animate({
left: '0px',
opacity: 1
}, 500);;
});
$('#three').click(function () {
$('#one-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#two-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#four-bck').animate({
left: '-650px;',
opacity: 0
}, 500).removeClass('animated');
$('#three-bck').addClass('animated').animate({
left: '-650px;',
opacity: 0
}, 500);
});
});
最佳答案
除了修复 css 和 removeClass 问题之外,您真的可以尝试简化它。与其将事件处理程序绑定(bind)到这些 ID 中的每一个,不如维护起来令人头疼,因为它们都做同样的事情。您可以将数据属性添加到 anchor 标记,即 data-target="#three-bck"
并选择它们进行动画处理。它可以全部放在一个事件处理程序中。
HTML:
<ul>
<li><a id="one" href="#" class="proBtn" data-target="#one-bck">block</a>
</li>
<li><a id="two" href="#" class="proBtn" data-target="#two-bck">test</a>
</li>
<li><a id="three" href="#" class="proBtn" data-target="#three-bck">test</a>
</li>
<li><a id="four" href="#" class="proBtn" data-target="#four-bck">Lists</a>
</li>
<li><a href="#" class="proBtn">hello</a>
</li>
<li><a href="#" class="proBtn">test</a>
</li>
</ul>
JS:
$(document).ready(function () {
$('.proBtn').click(function () {
$('li').removeClass('active').find('a').removeClass('blue'); //chain it
var $this = $(this); //cache this first
$this.addClass('blue').closest("li").addClass('active');
$('.mid-block.animated').animate({ //start animate for reverse in case if there is anything already selected
left: '-650px',
opacity: 0
}, 500, function(){
$(this).removeClass('animated'); //once done remove its class
}).promise().done(function () { //once this is done start animating your target by selecting the target element from its own data attribute
$($this.data('target')).addClass('animated').stop(true, true).animate({
left: '0px',
opacity: 1
}, 500);
});
});
});
关于javascript - Jquery animate() 问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18935007/