ios - 使用 Array.filter 而不是对象获取索引列表

Question

有什么方法可以获取过滤索引而不是对象的列表。

class Object
{
 var name
 var goal
}

var array<Object> = Array<Object>()

var filteredIndexes = array.filter{$0.name = "Sane"} // How to implement this?

Answer 1

有多种方法可以实现您的目标。例如，您可以过滤 Array.indices 而不是数组本身。

独立示例:

struct Object {
    let name:String
    let goal:String
}

let objects = [Object(name: "John", goal: "a"),Object(name: "Jane", goal: "a"),Object(name: "John", goal: "c"),Object(name: "Pete", goal: "d")]
let nameToBeFound = "John"
let filteredIndices = objects.indices.filter({objects[$0].name == nameToBeFound}) //[0,2]