jquery - 具有不同错误类别的单个 ID

Question

我有一个带有 id (form_select) 的表单，它有 2 个错误类别(errorIdentification 和 errorIdentification1)。

$('#form_select').validate({
  rules: {
    'user_name' : {
       required: true
       },
    'password'   : {
       required: true
    }
  },
  messages: {
    'user_name' : {
       required: 'From date is required!'
      },
    'password'   : {
       required: 'To date is required!'
      }
  },
  errorClass: **'errorIdentification'**,
  errorPlacement: function(err, element) {
  err.insertBefore(element);
  },
  submitHandler: function(form) {

  form.submit();
  }
});


$('#form_select').validate({
  rules: {
    'from' : {
       required: true
       },
    'to'   : {
       required: true
    }
  },
  messages: {
    'from' : {
       required: 'From date is required!'
      },
    'to'   : {
       required: 'To date is required!'
      }
  },
  errorClass: **'errorIdentification1'**,
  errorPlacement: function(err, element) {
  err.insertBefore(element);
  },
  submitHandler: function(form) {

  form.submit();
  }
});

问题在于验证表单，所有字段(用户名、密码、发件人和收件人)都获得相同的错误类 errorIdentification，这是(用户名和密码)的第一个错误类

如何使用不同的错误类来实现它？

Answer 1

像这样更改您的第二个表单脚本；

$('#form_select').validate({
  rules: {
    'from' : {
       required: true
       },
    'to'   : {
       required: true
    }
  },
  messages: {
    'from' : {
       required: 'From date is required!'
      },
    'to'   : {
       required: 'To date is required!'
      }
  },
  errorClass: **'errorIdentification1'**,
  errorPlacement: function(err, element) {
  err.insertBefore(element);
  },
  submitHandler: function(form) {

  form.submit();
  }
});