swift - 如何从 Swift 3 中的 TextView 中删除查找和共享

Question

我可以删除剪切、复制、粘贴、选择、全选

override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    if action == #selector(copy(_:)) || action == #selector(paste(_:)) || action == #selector(selectAll(_:)) || action == #selector(cut(_:))
    {
        return false
    }
    return super.canPerformAction(action, withSender: sender)
}

但我无法删除查找和分享

谁能建议我如何删除它？

Answer 1

如果您真的不想允许任何操作，为什么要专门检查每个操作？只需在您的方法中返回 false 即可。否则，您可以放置​​一个断点并查看您为“操作”调用的内容并为其添加另一个验证

override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    print("BlahTextView::canPerformAction: \(action)")
    return false
}

结果，您要删除的 2 个突出显示:

BlahTextView::canPerformAction: cut: BlahTextView::canPerformAction: copy: BlahTextView::canPerformAction: select: BlahTextView::canPerformAction: selectAll: BlahTextView::canPerformAction: paste: BlahTextView::canPerformAction: delete: BlahTextView::canPerformAction: _promptForReplace: BlahTextView::canPerformAction: _transliterateChinese: BlahTextView::canPerformAction: _showTextStyleOptions: BlahTextView::canPerformAction: _lookup: BlahTextView::canPerformAction: _define: BlahTextView::canPerformAction: _addShortcut: BlahTextView::canPerformAction: _accessibilitySpeak: BlahTextView::canPerformAction: _accessibilitySpeakLanguageSelection: BlahTextView::canPerformAction: _accessibilityPauseSpeaking: BlahTextView::canPerformAction: _share: BlahTextView::canPerformAction: makeTextWritingDirectionRightToLeft: BlahTextView::canPerformAction: makeTextWritingDirectionLeftToRight:

然后你可以做:

override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    if action == #selector(copy(_:)) ||
        action == #selector(paste(_:)) ||
        action == #selector(select(_:)) ||
        action == #selector(selectAll(_:)) ||
        action == #selector(cut(_:)) ||
        action == Selector(("_lookup:")) ||
        action == Selector(("_share:")) ||
        action == Selector(("_define:"))
    {
        return false
    }
    return super.canPerformAction(action, withSender: sender)
}

需要备用语法，因为这些方法未公开声明，如果您使用 #selector(share(:)) 示例，您将收到编译器错误。

查找 - 请使用 ((_define:)) 谢谢。