javascript - Switch 语句不更新 Document.getElementById()

Question

我有一个看起来像这样的 Switch 语句。

switch (rsCash.length){
case 1:
    document.getElementById("cash3").innerHTML = rsCash + "Gp";
    break;
case 2:
    document.getElementById("cash3").innerHTML = rsCash + "Gp";
    break;
case 3:
    document.getElementById("cash3").innerHTML = rsCash + "Gp";
    break;
case 4:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut1) + "k";
    break;
case 5:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut2) + "k";
    break;
case 6:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut3) + "k";
    break;
case 7:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut1) + "M";
    break;
case 8:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut2) + "M";
    break;
case 9:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut3) + "M";
    break;
case 10:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut4) + "M";
    break;
case 11:
    document.getElementById("cash3").innerHTML = rsCash.substring(0,cut5) + "M";
    break;

当 rsCash 变量发生变化时，它不会更新。

HTML 是。

<h1 id="RsMoney">RsCash:<b id="cash3">0 Gp</b></h1>

我已经尝试将 switch 语句放在一个每秒都会被调用的函数中，但它仍然不起作用

我已经将整个代码复制并粘贴到 JavaScript lint 中，它没有发现错误，谷歌浏览器也没有发现错误

Variable 在这里被这个函数改变。

function OpenCrate(){
if(Crates != 0){
var RewardNumber = Math.floor((Math.random() * 15)+ 1);
switch (RewardNumber){
case 1:
    rsCash = rsCash + 200000;
    document.getElementById("Log").innerHTML = "$200k was found!";
    break;
case 2:
    rsCash = rsCash + 25000;
    document.getElementById("Log").innerHTML = "$15 was found!";
    break;
case 3:
    rsCash = rsCash + 5000;
    document.getElementById("Log").innerHTML = "5k was found!";
    break;
case 4:
    rsCash = rsCash + 500000;
    document.getElementById("Log").innerHTML = "500k was found!";
    break;
case 5:
    rsCash = rsCash + 75000;
    document.getElementById("Log").innerHTML = "75k was found!";
    break;
case 6:
    rsCash = rsCash + 5000000;
    document.getElementById("Log").innerHTML = "5m was found!";
    break;
case 7:
    rsCash = rsCash + 275000;
    document.getElementById("Log").innerHTML = "275k was found!";
    break;
case 8:
    rsCash = rsCash + 5000;
    document.getElementById("Log").innerHTML = "5k was found!";
    break;
case 9:
    rsCash = rsCash + 15000;
    document.getElementById("Log").innerHTML = "15k was found!";
    break;
case 10:
    rsCash = rsCash + 8000;
    document.getElementById("Log").innerHTML = "8k was found!";
    break;
case 11:
    rsCash = rsCash + 35000;
    document.getElementById("Log").innerHTML = "35k was found!";
    break;
case 12:
    rsCash = rsCash + 125000;
    document.getElementById("Log").innerHTML = "125k was found!";
    break;
case 13:
    rsCash = rsCash + 80000;
    document.getElementById("Log").innerHTML = "80k was found!";
    break;
case 14:
    rsCash = rsCash + 600000;
    document.getElementById("Log").innerHTML = "600k was found!";
    break;
case 15:
    rsCash = rsCash + 12000;
    document.getElementById("Log").innerHTML = "12k was found!";
    break;
}

Answer 1

rsCash 是一个数字:

rsCash = rsCash + 200000;

但是你想把它的长度拉长:

switch (rsCash.length) ...

你不能那样做 - 你得到 undefined，所以你的 case 都没有触发。在获取长度之前，您需要将 rsCash 转换为字符串；像这样:

switch (rsCash.toString().length) ...