ios - 将字典数组快速转换为自定义对象

Question

我有:

    let countries : [[String : Any]] = [
            [
                "name" : "Afghanistan",
                "dial_code": "+93",
                "code": "AF"
            ],
            [
                "name": "Aland Islands",
                "dial_code": "+358",
                "code": "AX"
            ],
            [
                "name": "Albania",
                "dial_code": "+355",
                "code": "AL"
            ],
            [
                "name": "Algeria",
                "dial_code": "+213",
                "code": "DZ"
            ]
]

我想将所有这些字典数组添加到我的自定义对象中

let country:[Country] = countries

我的自定义对象如下所示:

class Country: NSObject {
        let name: String
        let dial_code : String
        let code: String

        init(name: String, dial_code: String, code: String) {
            self.name = name
            self.dial_code = dial_code
            self.code = code
        }
    }

我知道我需要一个遍历数组的循环，但我不知道下一步是什么。有一个例子会很棒。

Answer 1

你应该让你的国家符合Codable协议(protocol)，使用 JSONSerialization 将您的字典转换为 JSON 数据然后解码 Data使用 JSONDecoder , 注意你可以设置它的 keyDecodingStrategy属性(property)convertFromSnakeCase自动避免需要声明自定义编码键，如 dial_Code :

struct Country: Codable {
    let name: String
    let dialCode : String
    let code: String
}

---

do {
    let json = try JSONSerialization.data(withJSONObject: countries)
    let decoder = JSONDecoder()
    decoder.keyDecodingStrategy = .convertFromSnakeCase
    let decodedCountries = try decoder.decode([Country].self, from: json)
    decodedCountries.forEach{print($0)}
} catch {
    print(error)
}

---

Country(name: "Afghanistan", dialCode: "+93", code: "AF")

Country(name: "Aland Islands", dialCode: "+358", code: "AX")

Country(name: "Albania", dialCode: "+355", code: "AL")

Country(name: "Algeria", dialCode: "+213", code: "DZ")