swift - 使用 swift 搜索栏类别过滤器

Question

我正在尝试实现一个搜索栏，该搜索栏根据人物和地点对搜索查询进行分类，因此用户可以在两种搜索类别之间来回切换。我有为人们工作的搜索栏，但我无法弄清楚如何在 2 个搜索类别之间来回切换...我将如何实现它？ 下面是代码...

提前致谢!

//
//  SearchViewController.swift
//  TravelAppSwiftPrototype
//

import UIKit

class SearchViewController: UITableViewController, UITableViewDataSource, UITableViewDelegate, UISearchBarDelegate, UISearchDisplayDelegate {

    var persons = [People]()
    var place = [Places]()

    var filteredPersons = [People]()
     var filteredPlaces = [Places]()

    override func viewDidLoad() {
        // Sample Data for PeopleArray
        self.persons = [People(category:"People", name:"Anthony Valentine"),
            People(category:"People", name:"Ben Matthews"),
            People(category:"People", name:"Mark Druffel"),
            People(category:"People", name:"Brittany Donnelly"),
            People(category:"People", name:"Thomas Meier"),
            People(category:"People", name:"Alex Curtis"),
            People(category:"People", name:"David Moss"),
            People(category:"People", name:"Sara Flege"),
            People(category:"People", name:"Mark Cuban"),
            People(category:"People", name:"Elon Musk"),
            People(category:"People", name:"Steve Jobs"),
            People(category:"People", name:"Steve Meier"),
            People(category:"People", name:"Dan Meier"),
            People(category:"People", name:"Christine Meier"),
            People(category:"People", name:"Bill Gates"),
            People(category:"People", name:"Matt Harris")]


        // Sample Data for PlacesArray
        self.place = [Places(category:"People", place:"Rome, Italy"),
            Places(category:"Places", place:"Paris, France"),
            Places(category:"Places", place:"Barcelona, Spain"),
            Places(category:"Places", place:"Girona, Spain"),
            Places(category:"Places", place:"Lloret de Mar, Spain"),
            Places(category:"Places", place:"London, United Kingdom"),
            Places(category:"Places", place:"Perth, Australia"),
            Places(category:"Places", place:"Berlin, Germany"),
            Places(category:"Places", place:"Lyon, France"),
            Places(category:"Places", place:"Munich, Germany"),
            Places(category:"Places", place:"Bruges, Belgium"),
            Places(category:"Places", place:"Buenes Aires, Argentina"),
            Places(category:"Places", place:"Milan, Italy")]



        // Reload the table
        self.tableView.reloadData()
    }

     //how to implement search filtering for places...?????
    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        if tableView == self.searchDisplayController!.searchResultsTableView {
            return self.filteredPersons.count
        } else {
            return self.persons.count
        }
    }



    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
        //ask for a reusable cell from the tableview, the tableview will create a new one if it doesn't have any
        let cell = self.tableView.dequeueReusableCellWithIdentifier("SearchFriendsCell") as UITableViewCell

        var people : People
        // Check to see whether the normal table or search results table is being displayed and set the Candy object from the appropriate array
        if tableView == self.searchDisplayController!.searchResultsTableView {
            people = filteredPersons[indexPath.row]
        } else {
            people = persons[indexPath.row]
        }

        // Configure the cell
        cell.textLabel.text = people.name
        cell.accessoryType = UITableViewCellAccessoryType.DisclosureIndicator

        return cell
    }

    func filterContentForSearchText(searchText: String, scope: String = "All") {
        self.filteredPersons = self.persons.filter({( people : People) -> Bool in
            var categoryMatch = (scope == "All") || (people.category == scope)
            var stringMatch = people.name.rangeOfString(searchText)
            return categoryMatch && (stringMatch != nil)
        })
    }

    func searchDisplayController(controller: UISearchDisplayController!, shouldReloadTableForSearchString searchString: String!) -> Bool {
        let scopes = self.searchDisplayController!.searchBar.scopeButtonTitles as [String]
        let selectedScope = scopes[self.searchDisplayController!.searchBar.selectedScopeButtonIndex] as String
        self.filterContentForSearchText(searchString, scope: selectedScope)
        return true
    }

    func searchDisplayController(controller: UISearchDisplayController!,
        shouldReloadTableForSearchScope searchOption: Int) -> Bool {
            let scope = self.searchDisplayController!.searchBar.scopeButtonTitles as [String]
            self.filterContentForSearchText(self.searchDisplayController!.searchBar.text, scope: scope[searchOption])
            return true
    }

    override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
        self.performSegueWithIdentifier("FriendsDetail", sender: tableView)
    }

    override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!) {
        if segue.identifier == "FriendsDetail" {
            let candyDetailViewController = segue.destinationViewController as UIViewController
            if sender as UITableView == self.searchDisplayController!.searchResultsTableView {
                let indexPath = self.searchDisplayController!.searchResultsTableView.indexPathForSelectedRow()!
                let destinationTitle = self.filteredPersons[indexPath.row].name
                candyDetailViewController.title = destinationTitle
            } else {
                let indexPath = self.tableView.indexPathForSelectedRow()!
                let destinationTitle = self.persons[indexPath.row].name
                candyDetailViewController.title = destinationTitle
            }
        }
    }



    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }


    /*
    // MARK: - Navigation

    // In a storyboard-based application, you will often want to do a little preparation before navigation
    override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
        // Get the new view controller using segue.destinationViewController.
        // Pass the selected object to the new view controller.
    }
    */

}



//  Friends.swift
//  TravelAppSwiftPrototype
//
import Foundation

struct People {
    let category : String
    let name : String
}



//  Places.swift
//  TravelAppSwiftPrototype
//
import Foundation

struct Places {
    let category : String
    let place : String
}

Answer 1

关键是这个方法:

func filterContentForSearchText(searchText: String, scope: String = "All") {
    self.filteredPersons = self.persons.filter({( people : People) -> Bool in
        var categoryMatch = (scope == "All") || (people.category == scope)
        var stringMatch = people.name.rangeOfString(searchText)
        return categoryMatch && (stringMatch != nil)
    })
}

您需要以考虑范围按钮设置的方式编写该方法。然后，您将自己设置为搜索栏的代表，以便您听到有关正在更改的范围按钮的消息。当它发生变化时，进行过滤并重新加载结果表。