当“address”数组不为空时效果很好。但是当“地址”数组为空时它会失败。任何帮助将不胜感激。我有地址对象的结构。基本上“地址”是“地址”类型的对象数组,但是本地址为空时它会失败。
{
"success": "1",
"message": "You have succesfully verified your mobile no",
"details": {
"customer_id": 825,
"is_delivery_available": "0",
"is_registration_complete": "0",
"is_customer_verified": "0",
"customer_status": "0",
"cart_count": "0",
"name_type": "mr",
"firstname": "",
"lastname": "",
"full_name": "",
"pincode": "",
"profile_pic": "",
"mobile": "8583846677",
"email": "",
"address": [
],
"referral_code": ""
}
}
以上是我尝试在 Swift4 中使用 Codable 解码的 JSON。
import Foundation
struct Signup: Codable {
var success:String?
var message:String?
var details:Details?
private enum CodingKeys: String, CodingKey { case success, message, details }
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
success = try values.decode(String.self, forKey: .success)
message = try values.decode(String.self, forKey: .message)
if let _details = try? values.decode(Details.self, forKey: .details) {
details = _details
}
}
}
struct Details: Codable {
var address:[Address]?
var cart_count:String?
var customer_id:String?
var customer_status:String?
var email:String?
var firstname:String?
var full_name:String?
var is_customer_verified:String?
var is_delivery_available:String?
var is_registration_complete:String?
var lastname:String?
var mobile:String?
var name_type:String?
var pincode:String?
var profile_pic:String?
var referral_code:String?
private enum CodingKeys: String, CodingKey { case address, cart_count, customer_id, customer_status, email, firstname, full_name, is_customer_verified, is_delivery_available, is_registration_complete, lastname, mobile, name_type, pincode, profile_pic, referral_code }
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
****-->>> Issue is in this line. How to handle empty array while decoding. <<<--****
address = try? values.decode([Address].self, forKey: .address)
cart_count = try values.decode(String.self, forKey: .cart_count)
customer_id = try values.decode(String.self, forKey: .customer_id)
customer_status = try values.decode(String.self, forKey: .customer_status)
email = try values.decode(String.self, forKey: .email)
firstname = try values.decode(String.self, forKey: .firstname)
full_name = try values.decode(String.self, forKey: .full_name)
is_customer_verified = try values.decode(String.self, forKey: .is_customer_verified)
is_delivery_available = try values.decode(String.self, forKey: .is_delivery_available)
is_registration_complete = try values.decode(String.self, forKey: .is_registration_complete)
lastname = try values.decode(String.self, forKey: .lastname)
mobile = try values.decode(String.self, forKey: .mobile)
name_type = try values.decode(String.self, forKey: .name_type)
pincode = try values.decode(String.self, forKey: .pincode)
profile_pic = try values.decode(String.self, forKey: .profile_pic)
referral_code = try values.decode(String.self, forKey: .referral_code)
}
}
struct Address: Codable {
var address_default:String?
var address_id:String?
var address_type:String?
var city:String?
var customer_id:String?
var flat_or_house_or_office_no:String?
var full_address:String?
var full_name:String?
var landmark:String?
var lat:String?
var lng:String?
var mobile:String?
var name_type:String?
var pincode:String?
var street_or_society_or_office_name:String?
}
我深陷其中。如何在 Swift4 Codable 中解码 json 数据时处理空数组。
最佳答案
我遇到了这个问题,我按照下面的方法解决了这个问题。
if let _address = try? values.decode([Address].self, forKey: .address) {
address = _address
} else {
address = []
}
你可以试一试。
2022.06.08 更新。
根据@Amin Benarieb
let _address = try? values.decode([Address].self, forKey: .address) ?? []
关于json - 如何在可编码解码过程中处理空数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50502409/