javascript - 如何让 Toggle button JS 继续工作？

我正在尝试使用切换按钮来更改消息，但不幸的是，如果您一直按它，它就不起作用。

这是我的 HTML 代码:

toggled = true;
togBtn.onclick = function() {
  var text = "SELL"
  if (!toggled) {
    document.getElementById("test1").style.display = "none";
    toggled = true;
  }
  if (toggled) {
    document.getElementById("test1").innerHTML = text;
    toggled = false;
  }
};

#newsletter {
  color: #ffffff;
  background: #1d3030;
  height: 60px;
}

#newsletter h1 {
  float: left;
  padding-left: 600px;
}

#newsletter form {
  float: right;
}

.switch {
  position: relative;
  display: inline-block;
  width: 115px;
  height: 34px;
}

.switch input {
  display: none;
}

.slider {
  position: absolute;
  cursor: pointer;
  top: 0;
  left: 0;
  right: 0;
  bottom: 0;
  background-color: #e8491d;
  -webkit-transition: .4s;
  transition: .4s;
}

.slider:before {
  position: absolute;
  content: "";
  height: 26px;
  width: 26px;
  left: 4px;
  bottom: 4px;
  -webkit-transition: .4s;
  transition: .4s;
}

input:checked+.slider {
  background-color: #2196F3;
}

input:focus+.slider {
  box-shadow: 0 0 1px #2196F3;
}

input:checked+.slider:before {
  -webkit-transform: translateX(80px);
  -ms-transform: translateX(80px);
  transform: translateX(80px);
}

.on {
  display: none;
}

.on,
.off {
  color: white;
  position: absolute;
  transform: translate(-50%, -50%);
  top: 50%;
  left: 50%;
  font-size: 10px;
}

input:checked+.slider .on {
  display: block;
}

input:checked+.slider .off {
  display: none;
}

.slider.round {
  border-radius: 34px;
}

.slider.round:before {
  border-radius: 50%;
}

<body>
  <section id="newsletter">
    <div class="container">
      <h1 id="test1">BUY</h1>
      <form method="post" action="">
        <label class="switch">
    <input type="checkbox" id="togBtn" class="togBtn">
    <div class="slider round">
    <span class="on" name="on" id="on">SELL</span>
    <span class="off" name="off" id="off">BUY</span>
    </div>
    </label>
      </form>
    </div>
    <div class="box">
    </div>
  </section>
</body>

我添加了变量 toggled 以用于更改 HTML 中的名称。该按钮仅适用于两次点击，之后，它就不再起作用了。

最佳答案

这比你做的要简单得多。不需要两个 span 元素，然后切换每个元素的 display。只需使用一个 span 并根据当前文本更新其文本。

此外，您的 HTML 无效。您错误地使用了 label 元素。

var btn = document.querySelector(".slider.round");
var output = document.querySelector(".onOff");
var test1 = document.getElementById("test1");
btn.addEventListener("click", function () {
  var text = (output.textContent === "Buy") ? "Sell" : "Buy";
  output.textContent = text;
  test1.textContent = text;
});

#newsletter {
      color: #ffffff;
      background: #1d3030;
      height: 60px;
}

#newsletter h1 {
      float: left;
      padding-left: 600px;
}

#newsletter form {
      float: right;
}

.switch {
      position: relative;
      display: inline-block;
      width: 115px;
      height: 34px;
}

.switch input {
  display: none;
}

.slider {
     position: absolute;
      cursor: pointer;
      top: 0;
      left: 0;
      right: 0;
      bottom: 0;
      background-color: #e8491d;
      -webkit-transition: .4s;
      transition: .4s;
}

    .slider:before {
      position: absolute;
      content: "";
      height: 26px;
      width: 26px;
      left: 4px;
      bottom: 4px;
      -webkit-transition: .4s;
      transition: .4s;
    }

    input:checked + .slider {
      background-color: #2196F3;
    }

    input:focus + .slider {
      box-shadow: 0 0 1px #2196F3;
    }

    input:checked + .slider:before {
      -webkit-transform: translateX(80px);
      -ms-transform: translateX(80px);
      transform: translateX(80px);
    }

    .onOff {
      color: white;
      position: absolute;
      transform: translate(-50%,-50%);
      top: 50%;
      left: 50%;
      font-size: 10px;
    }

    input:checked + .slider .on {
      display: block;
    }

    input:checked + .slider .off {
      display: none;
    }

    .slider.round {
      border-radius: 34px;
    }

    .slider.round:before {
      border-radius: 50%;
    }

<section id="newsletter">
  <div class="container">
    <h1 id="test1">BUY</h1>
    <form method="post" action="">
    
      <!-- You shouldn't use a label here -->
      <div class="switch">
      
        <input type="checkbox" id="togBtn" class="togBtn">
        
        <div class="slider round">
          <span class="onOff" name="onOff">Buy</span>
        </div>
        
      </div>
      
    </form>
  </div>
  <div class="box"></div>
</section>

关于javascript - 如何让 Toggle button JS 继续工作？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/47188661/

javascript - 如何让 Toggle button JS 继续工作？

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