ios - 如何确保相同的继承层次结构，例如对于 MVVM

Question

我有一个基本的 ViewController 和一个基本的 ViewModel。基础 ViewModel 由基础 ViewController 使用。此外，我有 2 个 ViewController 子类和 2 个 ViewModel 子类需要一起使用。

例子:

class BaseViewModel {
    func somethingBasic() {}
}

class ConcreteViewModel1: BaseViewModel {
    func somethingConcrete1() {}
}

class ConcreteViewModel2: BaseViewModel {
    func somethingConcrete2() {}
}

class BaseViewController {
    let viewModel: BaseViewModel

    init(with viewModel: BaseViewModel) {
        self.viewModel = viewModel
    }
}

class ConcreteViewController1: BaseViewController {
    init(with viewModel: ConcreteViewModel1) {
        super.init(with: viewModel)
    }

    func useViewModel() {
        viewModel.somethingBasic()
        viewModel.somethingConcrete1() //this does not work
    }
}

class ConcreteViewController2: BaseViewController {
    init(with viewModel: ConcreteViewModel2) {
        super.init(with: viewModel)
    }

    func useViewModel() {
        viewModel.somethingBasic()
        viewModel.somethingConcrete2() //this does not work
    }
}

问题是:使 viewmodel.somethingConcrete1() 和 viewmodel.somethingConcrete2() 工作的首选解决方案是什么？

Answer 1

为此尝试使用Generics。

在 BaseViewController 中创建 init 接受一个 generic parameter T constrained to type BaseViewModel，即

class BaseViewController<T: BaseViewModel> {
    let viewModel: T

    init(with viewModel: T) {
        self.viewModel = viewModel
    }
}

现在从 BaseViewController 继承 ConcreteViewController1 和 ConcreteViewController2 为通用参数 T，即

class ConcreteViewController1: BaseViewController<ConcreteViewModel1> {
    func useViewModel() {
        viewModel.somethingBasic()
        viewModel.somethingConcrete1()
    }
}

class ConcreteViewController2: BaseViewController<ConcreteViewModel2> {
    func useViewModel() {
        viewModel.somethingBasic()
        viewModel.somethingConcrete2()
    }
}