我正在使用 php 和 bootstrap 构建一个联系表单,我想在发生错误时显示 bootstrap 警报。所以我现在的问题是我已经让代码工作并且它检查错误但是在错误发生之前显示错误警报对话框
我试图将错误对话框移到 HTML 下方,但我仍然遇到同样的错误
$email = $name = $subject = $message = '';
$errors = ['email' => '', 'name' => '', 'subject' => '', 'message' => ''];
if (isset($_POST['submit'])) {
// check email
if (empty($_POST['email'])) {
$errors['email'] = "An email is required !";
} else {
$email = $_POST['email'];
if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
$errors['email'] = "Enter a validemail address !";
}
}
<div class="form-group">
<label for="email" class="bmd-label-floating">Email address</label>
<input type="email" class="form-control" name="email" value="<?php htmlspecialchars($email)?>">
<div class="mt-2 alert alert-warning alert-dismissible fade show" role="alert">
<?php echo $errors['email'] ?>
</div>
</div>
预期的行为应该是在错误发生时在错误对话框中显示错误,而不是在错误发生之前显示错误对话框
最佳答案
您想用 if
包装模态以检查是否确实存在错误。
<?php if($errors['email']): ?>
<div class="mt-2 alert alert-warning alert-dismissible fade show" role="alert">
<?php echo $errors['email'] ?>
</div>
<?php endif; ?>
关于php - 在php中使用bootstrap发生错误时如何显示错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56819066/