我有这个位来检索两个用户之间的所有消息:
let user1 = "john"
let user2 = "mark"
let predicateUser1To2 = NSPredicate(format: "user1 == %@", user1)
let predicateUser2From1 = NSPredicate(format: "user2 == %@", user2)
let predicateUser2To1 = NSPredicate(format: "user2 == %@", user1)
let predicateUser1From2 = NSPredicate(format: "user1 == %@", user2)
let predicate1To2 = NSCompoundPredicate(andPredicateWithSubpredicates: [predicateUser1To2, predicateUser2From1])
let predicate2To1 = NSCompoundPredicate(andPredicateWithSubpredicates: [predicateUser1From2, predicateUser2To1])
let predicate = NSCompoundPredicate(orPredicateWithSubpredicates: [predicate1To2, predicate2To1])
let query = CKQuery(recordType: "Chat", predicate: predicate)
但是它抛出了下面的错误。看起来它被正确评估了,为什么它错了!?
*** Terminating app due to uncaught exception 'CKException', reason: 'Invalid predicate: (user1 == "john" AND user2 == "mark") OR (user1 == "mark" AND user2 == "john") (Error Domain=CKErrorDomain Code=12 "(user1 == "john" AND user2 == "mark") OR (user1 == "mark" AND user2 == "john") is not a comparison predicate" UserInfo={NSLocalizedDescription=(user1 == "john" AND user2 == "mark") OR (user1 == "mark" AND user2 == "john") is not a comparison predicate, ck_isComparisonError=true})'
最佳答案
CloudKit 不支持 OR 查询。有关详细信息,请参阅: https://developer.apple.com/library/ios/documentation/CloudKit/Reference/CKQuery_class/
在很多情况下,您可以通过使用 in
谓词来解决这个问题,但这只适用于一个字段。在您的情况下,您可能会考虑像这样的谓词:
NSPredicate(format: "user1 in %@ AND user2 in %@", ["john", "mark"], ["john", "mark"])
这个仍然与您的样本不完全相同。 user1 可能与 user2 相同。例如,两者都可以是标记。在您的情况下,该记录未被选中,而在上面的示例中被选中。您可以添加一个额外的 AND 条件来排除这些条件。您可以添加:AND user1 != user2
如果查询变得更加复杂并且无法进行 in
查询,那么您可以执行 2 个查询并合并结果。
关于IOS- swift : OrPredicate in CloudKit results in invalid,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37202096/