javascript - 是否可以在 Javascript 中将选择器作为函数参数传递？

Question

我正在尝试为特定应用程序开发一种幻灯片。我在增加要显示的 div 时遇到了一些问题。 我需要将选择器及其位置传递给它，从而增加它的位置。

检查我需要做的代码:

HTML:

    <div name="div-default" class="title-result">
        <?php
            echo "$name";
        ?>
    </div>
    <div name="div01" id="div01" class="title-result">
        <?php
            echo "Seu número de Personalidade é: $numerologia[0]";
        ?>
    </div>
    <div name="div02" class="title-result">
        <?php
            echo "Seu número de Destino é: $numerologia[1]";
        ?>
    </div>
    <div name="div03" class="title-result">
        <?php
            echo "Seu número de Lição de Vida é: $numerologia[2]";
        ?>
    </div>

    <div>
        <button onclick="mudarDivNext([name ^= div0]:nth-child(SEND_ITS_POSITION_HERE))" id="next" class="change-div"></button>
     </div>

CSS:

 //here i define that the first div is visible, and the next ones invisible
    div[name ^= div0]:nth-child(2){
        display: inherit;
    }

    div[name ^= div0]{
        display: none;
    }

Javascript:

//This script already works for a fix position (from 2 for 3, for example) - need to make it work for all the divs.
function mudarDivNext(){
    var n = 2;
    $("[name ^= div0]:nth-child("+n+")").css("display", "none");
    $("[name ^= div0]:nth-child("+(n+1)+")").css("display", "inherit");
}

Answer 1

有几点，在使用内联函数调用时不要忘记引号，并使用字符串连接来发送参数:

mudarDivNext("[name ^= div0]:nth-child(" + variable + ")")