我正在尝试创建一个简单的表单验证，并且在设置所有字段之前不会提交表单。我这里有两个文件。 -表单.php -process.php
由于某些原因，$error 不会出现，radio button 也不会提交。有什么问题吗？
这是 form.php:
<?php
if(isset($_GET['error']) && $_GET['error']!=""){
echo $_GET['error'];
}
?>
<body>
<form action="process.php" method="POST">
<p>
<label for="name">Your Name:</label>
<input type="text" name="name" id="name" value="">
</p>
<p>
<label for="location">Dojo Location:</label>
<select name="location">
<option value="Mountain View">Mountain View</option>
<option value="San Francisco">San Francisco</option>
<option value="South Korea">South Korea</option>
<option value="Philippines">Philippines</option>
</select>
</p>
<p>
<label for="language">Favorite Language:</label>
<select name="language">
<option value="JavaScript">JavaScript</option>
<option value="PHP">PHP</option>
<option value="Ruby">Ruby</option>
<option value="Python">Python</option>
</select>
</p>
<p>
<label for="comment">Comment: (Optional)</label><br/>
<textarea rows="10" cols="50" name="comment"></textarea>
</p>
<p>
<label for="comment">Can we store cookies in your computer?</label>
<input type="radio" name="cookies" value="yes">Yes
<input type="radio" name="cookies" value="no">No
</p>
<input type="submit" value="Submit">
</form>
这是 process.php:
<?php
if (isset($_POST["submit"])) {
if (empty($_POST["name"])) {
$Error = "Missing Name";
}
if (empty($_POST["location"])) {
$Error = "Missing Location";
}
if (empty($_POST["language"])) {
$Error = "Missing language";
}
if (empty($_POST["cookies"])) {
$Error = "Select cookies";
}
}else{
$name = $_POST['name'];
$location = $_POST['location'];
$language = $_POST['language'];
$comment = $_POST['comment'];
$cookies = $_POST['cookies'];
}
if($Error!=""){
header("Location:form.php?error=".$Error);
}
?>
<h2>Submitted Information:</h2>
<p><?php echo "NAME: {$name}"; ?> </p>
<p><?php echo "DOJO LOCATION: {$location}"; ?></p>
<p><?php echo "FAVORITE LANGUAGE: {$language}:"; ?> </p>
<p><?php echo "COMMENT: {$comment}"; ?></p>
<p><?php echo "COOKIES: {$cookies}"; ?></p>
有什么想法吗？
最佳答案
在你的 process.php
中尝试这样的事情 if($Error!=""){
header("Location:form.php?error=".$Error);
}
在你的form.php
if(isset($_GET['error']) && $_GET['error']!=""){
echo $_GET['error'];
}
在您的 process.php 中将代码更改为
<?php
if (isset($_POST["submit"])) {
$Error ="";
if (isset($_POST["name"]) && $_POST["name"]!="") {
$Error = "Missing Name";
}
if (isset($_POST["location"]) && $_POST["location"]!="") {
$Error = "Missing Location";
}
if (isset($_POST["language"]) && $_POST["language"]!="") {
$Error = "Missing language";
}
if (isset($_POST["cookies"]) && $_POST["cookies"]!="") {
$Error = "Select cookies";
}
if($Error!=""){
header("Location:form.php?error=".$Error);
}
$name = $_POST['name'];
$location = $_POST['location'];
$language = $_POST['language'];
$comment = $_POST['comment'];
$cookies = $_POST['cookies'];
}
?>
关于PHP 简单表单验证，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/31221938/