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我正在使用 HTML、CSS 和 PHP 制作一个简单的表单。
目前,该表单向已识别的收件人发送一封电子邮件,但不包含来自该表单的任何信息,仅包含在 $formcontent 中识别的标题。
HTML
<form method ="post" action="index.php">
<input name="name" type="text" class="feedback-input" placeholder="Name" />
<input name="email" type="text" class="feedback-input" placeholder="Email" />
<textarea name="message" class="feedback-input" placeholder="message"></textarea>
<input id="submit" name="submit" type="submit" value="SUBMIT"/>
</form>
CSS
form { max-width:455px; margin-right:45px; margin-top:10px; float: right; display: inline; }
.feedback-input {
color:white;
font-family: Helvetica, Arial, sans-serif;
font-weight:500;
font-size: 18px;
border-radius: 5px;
line-height: 22px;
background-color: transparent;
border:2px solid #CC6666;
transition: all 0.3s;
padding: 13px;
margin-bottom: 15px;
width:100%;
box-sizing: border-box;
outline:0;
}
.feedback-input:focus { border:2px solid #CC4949; }
textarea {
height: 60px;
line-height: 60%;
resize:vertical;
}
[type="submit"] {
font-family: 'Montserrat', Arial, Helvetica, sans-serif;
width: 100%;
background:#CC6666;
border-radius:5px;
border:0;
cursor:pointer;
color:white;
font-size:24px;
padding-top:10px;
padding-bottom:10px;
transition: all 0.3s;
margin-top:-4px;
font-weight:700;
}
[type="submit"]:hover { background:#CC4949; }
PHP
<?php
$name = $_post['name'];
$email = $_post['email'];
$message = $_post['message'];
$formcontent = "From: $name \n Message: $message";
$recipient = 'info@beardmore.cc';
$subject = 'Beardmore.cc contact form';
$mailheader = "From: $email \r\n";
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
echo "Thank You!";?>
最佳答案
作为Albzi注意到in their comment ,在 PHP 中,这种情况很重要,您需要编辑代码以使用 $_POST
而不是 $_post
:
<?php
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$formcontent = "From: $name \n Message: $message";
$recipient = 'info@beardmore.cc';
$subject = 'Beardmore.cc contact form';
$mailheader = "From: $email \r\n";
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
echo "Thank You!";?>
您还应该清理您的变量,在这种状态下您的代码未受到恶意用户的保护。此外,检查它们是否设置为 isset
功能。
关于php - 表单发送空白值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33152827/