我有一个 HTML 表单，用户可以在其中输入他/她的电子邮件 ID 进行注册，一切正常，它会检查有效的电子邮件 ID 并注册电子邮件 ID!但是当我应用新代码来检查用户是否已经注册时，它不起作用!
下面是我的Html页面
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>Sign Up - MOBTRICKS</title>
<!-- CSS -->
<link rel="stylesheet" href="http://fonts.googleapis.com/css?family=Lobster">
<link rel='stylesheet' href='http://fonts.googleapis.com/css?family=Lato:400,700'>
<link rel="stylesheet" href="assets/bootstrap/css/bootstrap.min.css">
<link rel="stylesheet" href="assets/font-awesome/css/font-awesome.min.css">
<link rel="stylesheet" href="assets/css/style.css">
<!-- HTML5 Shim and Respond.js IE8 support of HTML5 elements and media queries -->
<!-- WARNING: Respond.js doesn't work if you view the page via file:// -->
<!--[if lt IE 9]>
<script src="https://oss.maxcdn.com/libs/html5shiv/3.7.0/html5shiv.js"></script>
<script src="https://oss.maxcdn.com/libs/respond.js/1.4.2/respond.min.js"></script>
<![endif]-->
<!-- Favicon and touch icons -->
<link rel="shortcut icon" href="assets/ico/fa.png">
<link rel="apple-touch-icon-precomposed" sizes="144x144" href="assets/ico/apple-touch-icon-144-precomposed.png">
<link rel="apple-touch-icon-precomposed" sizes="114x114" href="assets/ico/apple-touch-icon-114-precomposed.png">
<link rel="apple-touch-icon-precomposed" sizes="72x72" href="assets/ico/apple-touch-icon-72-precomposed.png">
<link rel="apple-touch-icon-precomposed" href="assets/ico/apple-touch-icon-57-precomposed.png">
<!-- <script type="text/javascript">
function greeting(){
alert("Welcome ! Your Email : " + document.forms["form"]["email"].value + " has been registered under our records successfully !")
}
</script> -->
</head>
<body>
<!-- Header -->
<div class="container">
<div class="row header">
<div class="col-sm-4 logo">
<h1><a href=#>PQR</a> <span>.</span></h1>
</div>
<div class="col-sm-8 call-us">
<p>Mob: <span>+91-9530803237</span> | email: <span>ab.creations27@gmail.com</span>
</p>
</div>
</div>
</div>
<!-- Coming Soon -->
<div class="coming-soon">
<div class="inner-bg">
<div class="container">
<div class="row">
<div class="col-sm-12">
<center>
<i class="fa fa-cog fa-spin fa-3x fa-fw"></i>
<span class="sr-only">Loading...</span>
<h2>We're Coming Soon</h2>
<p>We are working very hard on the new version of our site. It will bring a lot of new features. Stay tuned!</p>
<div class="timer">
<div class="days-wrapper">
<span class="days"></span>
<br>days
</div>
<div class="hours-wrapper">
<span class="hours"></span>
<br>hours
</div>
<div class="minutes-wrapper">
<span class="minutes"></span>
<br>minutes
</div>
<div class="seconds-wrapper">
<span class="seconds"></span>
<br>seconds
</div>
</div>
</div>
</div>
</div>
</div>
</div>
<!-- Content -->
<div class="container">
<div class="row">
<div class="col-sm-12 subscribe">
<h3>Subscribe to our newsletter !!</h3>
<p>Sign up now to our newsletter and you'll be one of the first to know when the site is ready:</p>
<form class="form-inline" role="form" action="assets/subscribe.php" method="post">
<div class="form-group">
<label class="sr-only" for="subscribe-email">Email address</label>
<input type="text" name="email" placeholder="Enter your email..." class="subscribe-email form-control" id="subscribe-email">
</div>
<button type="submit" class="btn">Subscribe</button>
</form>
***
<div class="success-message"></div>
<div class="error-message"></div>***
</div>
</div>
<div class="row">
<div class="col-sm-12 social">
<a href="https://www.facebook.com/ashuart001/" data-toggle="tooltip" data-placement="top" title="Facebook"><i class="fa fa-facebook"></i></a>
<a href="#" data-toggle="tooltip" data-placement="top" title="Twitter"><i class="fa fa-twitter"></i></a>
<a href="https://github.com/ashu271994" data-toggle="tooltip" data-placement="top" title="GitHub">
<i class="fa fa-github"></i>
</a>
<a href="https://plus.google.com/+AshishBharwal" data-toggle="tooltip" data-placement="top" title="Google Plus"><i class="fa fa-google-plus"></i></a>
<a href="https://in.pinterest.com/ashishbharwal/" data-toggle="tooltip" data-placement="top" title="Pinterest"><i class="fa fa-pinterest"></i></a>
<a href="mailto:ab.creations27@gmail.com?subject=MOBTRICKS-Signup &body=Please send your query with valid details!" data-toggle="tooltip" data-placement="top" title="EMAIL"><i class="fa fa-envelope-o"></i></a>
</div>
</div>
</div>
<!-- Footer -->
<footer id="footer">
<ul class="copyright">
<li>© <a href="https://www.facebook.com/ASHISHBHARWAL001">ASHISH BHARWAL</a>
</li>
<li>Credits: <a href="https://www.facebook.com/ashuart001/">AB-Creations</a>
</li>
</ul>
</footer>
<!-- Javascript -->
<script src="assets/js/jquery-1.11.1.min.js"></script>
<script src="assets/bootstrap/js/bootstrap.min.js"></script>
ipt src="assets/js/jquery.backstretch.min.js"></script>
<script src="assets/js/jquery.countdown.min.js"></script>
<script src="assets/js/scripts.js"></script>
<!--[if lt IE 10]>
<script src="assets/js/placeholder.js"></script>
<![endif]-->
</body>
</html>
下面是我的 Subscriber.php 页面
<?php
// Email address verification
function isEmail($email)
{
return (preg_match("/^[-_.[:alnum:]]+@((([[:alnum:]]| [[:alnum:]][[:alnum:]-]*[[:alnum:]])\.)+(ad|ae|aero|af|ag|ai|al|am|an|ao|aq|ar|arpa|as|at|au|aw|az|ba|bb|bd|be|bf|bg|bh|bi|biz|bj|bm|bn|bo|br|bs|bt|bv|bw|by|bz|ca|cc|cd|cf|cg|ch|ci|ck|cl|cm|cn|co|com|coop|cr|cs|cu|cv|cx|cy|cz|de|dj|dk|dm|do|dz|ec|edu|ee|eg|eh|er|es|et|eu|fi|fj|fk|fm|fo|fr|ga|gb|gd|ge|gf|gh|gi|gl|gm|gn|gov|gp|gq|gr|gs|gt|gu|gw|gy|hk|hm|hn|hr|ht|hu|id|ie|il|in|info|int|io|iq|ir|is|it|jm|jo|jp|ke|kg|kh|ki|km|kn|kp|kr|kw|ky|kz|la|lb|lc|li|lk|lr|ls|lt|lu|lv|ly|ma|mc|md|mg|mh|mil|mk|ml|mm|mn|mo|mp|mq|mr|ms|mt|mu|museum|mv|mw|mx|my|mz|na|name|nc|ne|net|nf|ng|ni|nl|no|np|nr|nt|nu|nz|om|org|pa|pe|pf|pg|ph|pk|pl|pm|pn|pr|pro|ps|pt|pw|py|qa|re|ro|ru|rw|sa|sb|sc|sd|se|sg|sh|si|sj|sk|sl|sm|sn|so|sr|st|su|sv|sy|sz|tc|td|tf|tg|th|tj|tk|tm|tn|to|tp|tr|tt|tv|tw|tz|ua|ug|uk|um|us|uy|uz|va|vc|ve|vg|vi|vn|vu|wf|ws|ye|yt|yu|za|zm|zw)$|(([0-9][0-9]?|[0-1][0-9][0-9]|[2][0-4][0-9]|[2][5][0-5])\.){3}([0-9][0-9]?|[0-1][0-9][0-9]|[2][0-4][0-9]|[2][5][0-5]))$/i", $email));
}
if ($_POST) {
// Enter the email where you want to receive the notification when someone subscribes
$emailTo = 'ab.creations27@gmail.com';
$subscriber_email = addslashes(trim($_POST['email']));
if (!isEmail($subscriber_email)) {
$array = array();
$array['valid'] = 0;
$array['message'] = 'Insert a valid email address!';
echo json_encode($array);
// $msg="wrong answer";
// echo "<script type='text/javascript'>alert('$msg');</script>";
} else {
$host = "somehostname";
$user = "username";
$pwd = "password";
$db = "demo1";
$conn = new PDO("mysql:host=$host;dbname=$db", $user, $pwd);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
try {
$sql_insert = "SELECT * FROM demotable WHERE subs='$subscriber_email'";
$stmt1 = $conn->prepare($sql_insert);
$stmt1->execute();
$result = $stmt1->fetchColumn();
if ($result == 0) {
$sql_insert = "INSERT INTO demotable (subs)
VALUES ('$subscriber_email')";
$stmt = $conn->prepare($sql_insert);
$stmt->execute();
$array = array();
$array['valid'] = 1;
$array['message'] = "Your Email : $subscriber_email has been registered with us ! Thanks for your subscription!";
echo json_encode($array);
} else {
$array = array();
$array['valid'] = 2;
$array['message'] = "You are already registered !!";
echo json_encode($array);
}
}
catch (Exception $e) {
die(var_dump($e));
}
}
}
?>
现在，当我尝试添加一个无效的电子邮件 ID 时发生了什么，然后它在 HTML 页面中标记为无效的电子邮件 ID，但是当我添加一个新用户时，然后将数据添加到我的表中并显示消息，但在用户的情况下谁已经注册了它没有显示任何消息!我还尝试制作具有 "echo json_encode($array)" 的新函数；但这也行不通!告诉我我错过了什么或我的错误是什么!我正在尝试从过去 3 天开始对它进行排序!!
下面是我的 scripts.js 代码
$('.subscribe form').submit(function(e) {
e.preventDefault();
var postdata = $('.subscribe form').serialize();
$.ajax({
type: 'POST',
url: 'assets/subscribe.php',
data: postdata,
dataType: 'json',
success: function(json) {
if(json.valid == 0) {
$('.success-message').hide();
$('.error-message').hide();
$('.error-message').html(json.message);
$('.error-message').fadeIn();
}
else if (json.valid == 1){
$('.error-message').hide();
$('.success-message').hide();
$('.subscribe form').hide();
$('.success-message').html(json.message);
$('.success-message').fadeIn();
}
else {
$('.error-message').hide().empty();
$('.success-message').hide().empty();
$('.subscribe form').hide();
$('.success-message').html(json.message);
$('.success-message').fadeIn();
}
}
});
});
最佳答案
尝试改变
$result = $stmt1->fetchColumn();
到
$result = $stmt1->num_rows;
看看是否可行。
关于javascript - 如何通过php显示用户已经在html中注册的消息？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39376745/