我有一个使用 JqueryUI Mobile 的页面。更具体地说,它使用 JqueryMobile 列表
http://demos.jquerymobile.com/1.2.1/docs/lists/lists-ul.html
我喜欢 ListView 的外观、感觉和用法,但我遇到了问题。
用户需要能够快速点击链接,这对我现在的做法来说很难。该链接执行 PHP 函数,然后重定向回它们所在的页面,然后循环重新开始。现在我对 AJAX 越来越熟悉了,我希望能够让他们单击链接,它会更新数据库,然后调用我的 AJAX 脚本来更新数据而无需刷新页面。
这将使用户能够更快地完成任务,因为他们目前的大部分停机时间是刷新(或更准确地说是重定向回)页面所需的几秒钟。如果可能的话,他们希望能够每秒甚至更多地点击一个链接。
我的问题是:如何根据从 MySQLi 数据库动态生成的链接执行数据库更新而不需要用户刷新?我相信,一旦有了它,我还可以使用 Ajax 每四分之一左右更新一次列表。我考虑过使用按钮,但不确定如何将它与 ListView 联系起来,因为 ListView 似乎仅基于链接。
旁注 - 他们的 Ajax 标准实践是否应该经常更新?有什么我应该遵循的指导方针吗?
这是我当前代码的示例:
<?php
session_start();
if(isset($_SESSION['username']))
{
}
else
{
$_SESSION['error']="You are logged in.";
header('Location: index.php');
exit;
}
?><!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1, user-scalable=0"/> <!--320-->
<link rel="stylesheet" href="js/jquery.mobile-1.4.5.min.css">
<script src="js/jquery-1.11.3.min.js"></script>
<link rel="stylesheet" href="style.css">
<script src="js/jquery.mobile-1.4.5.min.js"></script>
<style>
.split-custom-wrapper {
/* position wrapper on the right of the listitem */
position: absolute;
right: 0;
top: 0;
height: 100%;
}
.split-custom-button {
position: relative;
float: right; /* allow multiple links stacked on the right */
height: 80%;
margin:10px;
min-width:3em;
/* remove boxshadow and border */
border:none;
moz-border-radius: 0;
webkit-border-radius: 0;
border-radius: 0;
moz-box-shadow: none;
webkit-box-shadow: none;
box-shadow: none;
}
.split-custom-button span.ui-btn-inner {
/* position icons in center of listitem*/
position: relative;
margin-top:50%;
margin-left:50%;
/* compensation for icon dimensions */
top:11px;
left:-12px;
height:40%; /* stay within boundaries of list item */
}
.ui-icon-delete:after{
background-color: #B22222 !important;
background-image:url("data:image/svg+xml;charset=US-ASCII,%3C%3Fxml%20version%3D%221.0%22%20encoding%3D%22iso-8859-1%22%3F%3E%3C!DOCTYPE%20svg%20PUBLIC%20%22-%2F%2FW3C%2F%2FDTD%20SVG%201.1%2F%2FEN%22%20%22http%3A%2F%2Fwww.w3.org%2FGraphics%2FSVG%2F1.1%2FDTD%2Fsvg11.dtd%22%3E%3Csvg%20version%3D%221.1%22%20id%3D%22Layer_1%22%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F2000%2Fsvg%22%20xmlns%3Axlink%3D%22http%3A%2F%2Fwww.w3.org%2F1999%2Fxlink%22%20x%3D%220px%22%20y%3D%220px%22%20%20width%3D%2214px%22%20height%3D%2214px%22%20viewBox%3D%220%200%2014%2014%22%20style%3D%22enable-background%3Anew%200%200%2014%2014%3B%22%20xml%3Aspace%3D%22preserve%22%3E%3Cpolygon%20fill%3D%22%23FFF%22%20points%3D%2214%2C3%2011%2C0%207%2C4%203%2C0%200%2C3%204%2C7%200%2C11%203%2C14%207%2C10%2011%2C14%2014%2C11%2010%2C7%20%22%2F%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3Cg%3E%3C%2Fg%3E%3C%2Fsvg%3E")
}
.ui-icon-home:after{
background-color: #A2CD5A !important;
}
.ui-icon-arrow-u-r:after{
background-color: #3D59AB !important;
}
</style>
</header>
</head><center> <h2 style="">Empty For now<br><br>
</h2></center>
<a href="home.php" class="ui-btn ui-icon-home ui-btn-icon-left" data-ajax='false'>HOME</a>
<a href="ViewOrderMobile.php" class="ui-btn ui-icon-edit ui-btn-icon-left" data-ajax='false'>VIEW / EDIT CURRENT LINE</a>
<br><br><br><br>
<center><center>
<div data-role="main" class="ui-content"style="margin-top:-75px;">
<h2 style=""></h2>
<ul data-role="listview">
<?php
include "../../includes/databaseconnections/demo/database_connection.php";
///////////////////////////////////////////////////////////////////////////////////////////////
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
else{}
$query = "SELECT * FROM Table1 LEFT JOIN Table2 USING (ID) WHERE Table1.feild1 = '0' ORDER BY dateSelected ASC LIMIT 25";
if ($result = mysqli_query($link, $query)) {
/* fetch associative array */
while ($row = mysqli_fetch_assoc($result)) {
if ($row['photoLink'] == NULL)
{
$row['photoLink'] = "endofgroup";
$row['lastName'] = "End Of Group " ;
$ID = "&ID=".$row['ID'];
}
if ($row[leftGym] == "1") { $flash = "style='color:#B22222;font-size:140%'";} else {$flash ="";}
echo "<li><a href='button1.php?sid=${row['ID']}' $flash style='font-size:140%;' width='25px' data-ajax='false'> {$row["lastName"]}, {$row["firstName"]} ({$row["pmBusNumber"]})</a><div class='split-custom-wrapper'>
<a href='button2.php?sID={$row['ID']}&lane=1{$ID}' data-role='button' class='split-custom-button' data-icon='delete' data-rel='dialog' data-theme='c' data-ajax='false' data-iconpos='notext'></a>
</div></li>";
}
/* free result set */
mysqli_free_result($result);
}
mysqli_close($link);
/////////////////////////////////////////////////////////////////////////////////
?>
</ul><br>
</div>
</div>
</div>
</body>
</html>
最佳答案
我已经在代码片段中添加了注释。如果您需要更多信息,请告诉我们。 基于 jquery ajax() v3.1.1
html:用 class=myCustomClass
更新列表中的 a
元素
<a href='button1.php?sid=${row['ID']}' $flash style='font-size:140%;' width='25px' data-ajax='false' class='myCustomClass'> {$row["lastName"]}, {$row["firstName"]} ({$row["pmBusNumber"]})</a>
<div class='split-custom-wrapper'>
<a href='button2.php?sID={$row['ID']}&lane=1{$ID}' data-role='button' class='myCustomClass split-custom-button' data-icon='delete' data-rel='dialog' data-theme='c' data-ajax='false' data-iconpos='notext'>
</a>
</div>
<span id="status"></span>
脚本:
$(function () {
//Attach the click event to Links only with class=myCustomClass and perform this function
$("a[class=myCustomClass]").on('click', function (e) {
e.preventDefault(); //preven the page from navigating, the default behaviour for a link
$.ajax({
url : this.href, //perform a ajax request with the link, GET in this case
/* type: POST, */
beforeSend : function () {
$("#status").text('Working..')
}
}).done(function (data) {
console.log(data); //do something with the data if any
}).fail(function (jqXHR, textStatus, errorThrown) {
console.log("ERROR"); //report in console for errors
console.info(jqXHR);
console.info(textStatus);
console.info(errorThrown);
}).always(function () {
//do this step every time
$("#status").text('completed..')
console.info("completed"); irrespective of result
});
})
关于javascript - 使用 JqueryUI Mobile ListView 替代超链接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41250584/