考虑以下代码 sample donut chart using jquery-flot ,现在我在点击 donut 时添加了“图像”类,我想在“图像”类中动态添加度数,以便点击的元素将在底部面朝下(就像在 -ve 侧y 轴)。`
var data = [{
label: "Pause",
data: 150
}, {
label: "No Pause",
data: 100
}, {
label: "yes Pause",
data: 80
}, {
label: "Sleeping",
data: 250
}];
var options = {
series: {
pie: {
show: true,
innerRadius: 0.5,
radius: 1,
startAngle: 1,
}
},
grid: {
hoverable: true,
clickable: true
},
legend: {
show: false
},
stroke: {
width: 4
},
tooltip: true,
tooltipOpts: {
cssClass: "flotTip",
content: "%s: %p.0%",
defaultTheme: false
}
};
$("#pie-placeholder").bind("plotclick", function(event, pos, obj) {
$("#pie-placeholder").addClass('image')
});
var plot = $.plot($("#pie-placeholder"), data, options);
`
注意:- 这是使用 Jquery flot 完成的
最佳答案
Here如果我猜对了,你可以找到我解决你问题的方法。
$("#pie-placeholder").bind("plotclick", function(event, pos, obj) {
if (obj) {
var percentInRads = 0.02;
var currSegmentInRads = percentInRads * obj.datapoint[0]
var currSegmentOffset = currSegmentInRads / 2;
var currSegmentStart = currSegmentOffset >= 0.5 ? -0.5 + currSegmentOffset : 0.5 - currSegmentOffset;
var total = 0;
var beforeTotal = 0;
for (var idx = 0; idx < data.length; idx++) {
var segment = data[idx];
if (idx < obj.seriesIndex) {
beforeTotal += segment.data;
}
total += segment.data;
}
var beforePart = (beforeTotal / total * 100) * percentInRads;
var chartStartAngle = currSegmentStart - beforePart;
options.series.pie.startAngle = chartStartAngle;
$.plot($("#pie-placeholder"), data, options);
console.log(obj.series);
}
});
关于javascript - 如何计算单击的 donut 元素的中点与负 y 轴之间的 Angular ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42470834/