通过单击面板打开 Accordion 的内容主体。这通常是最好的。我现在想做的是更改此行为，以便仅通过单击其中一个面板(或其他任何地方)中包含的链接来显示内容主体。希望这是有道理的。
首先:这可能吗？
这是现在的代码:
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
.accordion {
background-color: #fff;
color: #444;
cursor: pointer;
width: 103%;
border: none;
text-align: left;
outline: none;
font-size: 15px;
transition: 0.4s;
margin: -5px;
}
.bg {
width: 100%;
}
.active,
.accordion:hover {
background-color: #fff;
}
.panel {
padding: 50px 0px;
display: none;
width: 100%;
background-color: white;
overflow: hidden;
border-style: groove;
}
.accordion.active+div {
display: block
}
.column {
float: left;
width: 20%;
padding: 10px;
}
/* Clear floats after the columns */
.row:after {
content: "";
display: table;
clear: both;
}
</style>
</head>
<body>
<button class="accordion"><div class="parent">Only the following link should open the content panel: link_1</button>
<div class="panel">
<p>Content 1</p>
</div>
<button class="accordion">Only the following link should open the content panel: link_2</button>
<div class="panel">
<p>Content 2</p>
</div>
<button class="accordion">Only the following link should open the content panel: link_3</button>
<div class="panel">
<p>Content 3</p>
</div>
<button class="accordion">Only the following link should open the content panel: link_4</button>
<div class="panel">
<p>Content 4</p>
</div>
<script>
function scrollElmVert(el,num) { // to scroll up use a negative number
var re=/html$/i;
while(!re.test(el.tagName) && (1 > el.scrollTop)) el=el.parentNode;
if(0 < el.scrollTop) el.scrollTop += num;
}
var acc = document.getElementsByClassName("accordion");
var i;
var open = null;
for (i = 0; i < acc.length; i++) {
acc[i].addEventListener("click", function() {
if (open == this) {
open.classList.toggle("active");
open = null;
} else {
if (open != null) {
open.classList.toggle("active");
}
this.classList.toggle("active");
open = this;
//Scroll to clicked element
open.scrollIntoView();
scrollElmVert(open,-68);
}
});
}
</script>
</body>
</html>最佳答案
对 css 的改动很少，但总的来说它是一个 html 问题。您将需要有两个不同的元素或至少不同的类来区分打开 Accordion 的元素和不打开 Accordion 的元素
希望这就是您要找的。如果需要，很乐意解释或提供更好的解决方案。
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
.accordion {
background-color: #fff;
color: #444;
cursor: pointer;
border: none;
text-align: left;
outline: none;
font-size: 15px;
transition: 0.4s;
margin: -5px;
display: inline;
}
.not-accordion {
color: #444;
font-size: 15px;
display: inline-block;
}
.bg {
width: 100%;
}
.active,
.accordion:hover {
background-color: #fff;
}
.panel {
padding: 50px 0px;
display: none;
width: 100%;
background-color: white;
overflow: hidden;
border-style: groove;
}
.accordion.active+div {
display: block
}
.column {
float: left;
width: 20%;
padding: 10px;
}
/* Clear floats after the columns */
.row:after {
content: "";
display: table;
clear: both;
}
</style>
</head>
<body>
<div class="parent">
<p class='not-accordion'>Only the following link should open the content panel:</p> <button class="accordion">link_1</button>
<div class="panel">
<p>Content 1</p>
</div>
<p class='not-accordion'>Only the following link should open the content panel:</p> <button class="accordion">link_2</button>
<div class="panel">
<p>Content 2</p>
</div>
<p class='not-accordion'>Only the following link should open the content panel:</p> <button class="accordion">link_3</button>
<div class="panel">
<p>Content 3</p>
</div>
<p class='not-accordion'>Only the following link should open the content panel:</p> <button class="accordion">link_4</button>
<div class="panel">
<p>Content 4</p>
</div>
<script>
function scrollElmVert(el, num) { // to scroll up use a negative number
var re = /html$/i;
while (!re.test(el.tagName) && (1 > el.scrollTop)) el = el.parentNode;
if (0 < el.scrollTop) el.scrollTop += num;
}
var acc = document.getElementsByClassName("accordion");
var i;
var open = null;
for (i = 0; i < acc.length; i++) {
acc[i].addEventListener("click", function() {
if (open == this) {
open.classList.toggle("active");
open = null;
} else {
if (open != null) {
open.classList.toggle("active");
}
this.classList.toggle("active");
open = this;
//Scroll to clicked element
open.scrollIntoView();
scrollElmVert(open, -68);
}
});
}
</script>
</body>
</html>关于javascript - 链接的 Accordion 主体，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/48993676/